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2 years ago

Please answer this correctly

Mathematics

1 answer:

Lunna [17]2 years ago

6 0

Answer:

<h2>1.C. Statistics</h2><h2>2.A. Analysis </h2><h2>3.D. organizations </h2><h2>4.B. sample</h2><h2>5.A. Census</h2>

Step-by-step explanation:

1.Statistics is a branch of mathematics dealing with data collection, organization, analysis, interpretation and presentation.

2.Scientists do this by collecting data, analyzing it and drawing a conclusion. The whole process, from forming a hypothesis to announcing conclusions, is called the scientific method.

3.organizations

4.A sample is a sub collection of elements drawn from a population

5.A census is the collection of data from every element in a population.

<h3>ihope i help u again</h3>

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3 years ago

A perpendicular bisector, , is drawn through point C on .

Liula [17]

Answer:

The x-intercept of CD is B(18/5,0). The point C(32,-71) lies on the line CD.

Step-by-step explanation:

the x-intercept of CD is[ A(3,0) B(18/5,0) C(9,0) D(45/2,0) ] . Point [ A(-52,117) B(-20,57) C(32,-71) D(-54,-128) ] lies on CD.

Given :

CD is perpendicular bisector of AB.

The coordinates of point A are (-3, 2) and the coordinates of point B are (7, 6).

C is the midpoint of AB.

$C=(\frac{x_1+x_2}{2},\frac{y_1+y_2}{2})=(\frac{7-3}{2},\frac{2+6}{2})=(2,4)$

The coordinates of C are (2,4).

Line AB has a slope of: $m_1=\frac{y_2-y_1}{x_2-x_1}=\frac{6-2}{7-(-3)}=\frac{4}{10}=\frac{2}{5}$

The product of slopes of two perpendicular lines is -1. Since the line CD is perpendicular to AB, therefore the slope of CD : $m_2=-\frac{5}{2}$

The point slope form of a line is given by:

$y-y_1=m(x-x_1)$

The slope of line CD is $-\frac{5}{2}$ and the line passing through the point (2,4), the equation of line CD can be written as:

$y-4=-\frac{5}{2}(x-2)\\y=-\frac{5}{2}x+5+4\\y=-\frac{5}{2}x+9 .... (1)$

The equation of CD is $y=-\frac{5}{2}x+9$

In order to find the x-intercept, put y=0.

$0=-\frac{5}{2}x+9\\\frac{5}{2}x=9\\x=\frac{18}{5}$

Therefore the x-intercept of CD is B(18/5,0).

Put x=-52 in eq(1).

$y=-\frac{5}{2}(-52)+9=139$

Put x=-20 in eq(1).

$y=-\frac{5}{2}(-20)+9=59$

Put x=32 in eq(1)

$y=-\frac{5}{2}(32)+9=-71$

Put x=-54 in eq1).

$y=-\frac{5}{2}(-54)+9=144$

Thus, only point (32,-71) satisfies the equation of CD. Therefore the point C(32,-71) lies on the line CD.

8 0

3 years ago

Evaluate the expression<br> 3 4 5 x − 2 1 2 for x = − 10 .

Rina8888 [55]

Answer:

3,662

Step-by-step explanation:

It says that x= -10 so you have to multiply 345 by -10 because x is next to the number 345. Then you get the number -3450-212 from there you can see they are both negative so you can add them together and take out the negative symbol at the end. Hope that helped!

7 0

3 years ago

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nexus9112 [7]

Answer:

you don't have the graph

Step-by-step explanation:

3 0

2 years ago

Please answer this correctly​

Please answer this correctly