Step-by-step explanation:
Given: r = 4 cm
The surface area A of a sphere is given by
The perimeter = sum of all sides
= 120 + 80 + 50
= 250
So 250 - 3
247
Left space for gate
Now cost of fencing = Rs 20/per meter
= 247 × 20
= Rs 4,940
Now the area of the triangular park can be found using heron's formula
S = (a+b+c)/2
S = (120+80+50)/2
S = 250/2
S = 125
Now
Herons formula = √s(s-a)(s-b)(s-c)
√125(125-120)(125-80)(120-50)
√125(5)(45)(70)
√5×5×5×5×5×3×3×5×14
After Making pairs
5×5×5×3√14
375√14
Therefore 375√14m is the area of the triangular park
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It should be,
4x-8=2x-10 because you substitute that for y.
Now you do,
4x-2x because you do the opposite of the positive 2x as you bring it to the other side.
That is,
2x-8=10 now you bring the 8 to the other side.
2x=10+8 I added it because I do the opposite and it is a negative 8 so I add.
2x+18 now divide
x=9 that's the answer.
Answer:
45 square feet
Step-by-step explanation:
