Answer:
Nope
Step-by-step explanation:
To now if a triangle is a right angle, use Pythagoras Theorem,
a^2 + b^2 = c^2
C usually be the longest side of the triangle, C = 17
Then also let a and b be 6 and 13 respectively.
6^2 + 13^2 =205
C^2 = 205
C = sqrt(205) = 14.32
therefore no this is not a right angle triangle
Answer:
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Step-by-step explanation:
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Answer:
1/12
Step-by-step explanation:
multiple of 3 and a multiple of 4 implies it can only be 12.
Since you only have the numbers from 1 to 12,
the prob(the 12) = 1/12
Answer:
log (3) log (x)
--------- + ---------
2 2
Step-by-step explanation:
a. distribute to get → log (3) log (x)
--------- + ---------
2 2
Hope this helped! :)
Answer:
Actually it's not polygon. it's a nonagon. With r=8.65mm″, the law of cosines gives us side a:
a=√{b²+c²−2bc×cos40°}
a=√{149.645−149.645cos40°}
Area Nonagon = (9/4)a²cos40°
=9/4[149.645−149.645cos40°]cot20°
=336.70125[1−cos(40°)]cot(20°)
Applying an identity for the cos(40°) does not get us very far…
= 336.70125[1−(cos2(20°)−1)]cot(20°)
= 336.70125[2−cos2(20°)]cot(20°)
= 336.70125[2−(1−sin2(20°))]cot(20°)
= 336.70125[1+sin2(20°)]cos(20°)sin(20°)
= 336.70125[cot(20°)+sin(20°)cos(20°)]mm²
