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KIM [24]
3 years ago
13

The sum of the first and third of three consecutive even integers is 164. Find the three even integers.

Mathematics
1 answer:
givi [52]3 years ago
7 0
The three even integers are 80, 82, and 84.

The sum of the first (80) and the third (84) integers = 80 + 84 = 164, verifying our answer.

A simple way to figure this out is to divide 164 by 2, which gives you 82. From this answer, if we subtract 2 to get the first integer and add 2 to get the third integer while keeping 82 as the second integer, we end up with the correct sum of 164.

Hope this helps!
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Help...(MATH).......
Hitman42 [59]

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f(g(4)) = √(7•4 + b) = √(28 + b) = 6

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√(28 + b) = 6

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Answer:

Answer is option d)346.4 ft

Step-by-step explanation:

from \: the \: figure \\ AB = 300 \: ft \:  \:  \: angle \: C = 60  \:( theta)\: degress \\ in \: triangle \: ABC \: using \:  tan \: theta\\  \tan(60)  =  \frac{opposite \: side}{adjacent \: side}  \\  \tan(60)  =  \frac{300}{BC}  \\  \sqrt{3}  =  \frac{300}{BC}  \\ BC =  \frac{300}{ \sqrt{3} }  \\ BC = 100 \sqrt{3} ft \\ then \: in \: triangle \: ABD \: using \: tan \: theta \\ angle \: D = 30 \: degrees \: (theta) \\   \tan(30 )  =\frac{opposite \: side}{adjacent \: side} \\  \tan(30)   =  \frac{300}{BD}  \\  \frac{1}{ \sqrt{ 3} }  =  \frac{300}{BD}  \\ BD = 300 \sqrt{3}  \\ CD = BD - BC \\  = 300 \sqrt{3 }  - 100 \sqrt{3}  \\  = (300 - 100) \sqrt{3}  \\  = 200 \sqrt{3 }  \\  = 200 \times 1.732 \\  = 346.4 \: ft

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS FOR GIVING ME THE OPPORTUNITY</em><em> </em><em>TO ANSWER YOUR QUESTION</em><em>. </em>

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Step-by-step explanation:

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