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1 year ago

Find the area of the triangle shown

Mathematics

1 answer:

Artemon [7]1 year ago

7 0

Answer:

Area = 48m²

Step-by-step explanation:

S(ACB) = AB × AC/2

S(ACB) = 8 × 12/2 m²

S(ACB) = 48m²

Hope this helps and have a nice day

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FromTheMoon [43]

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3 years ago

Rewrite 9cos 4x in terms of cos x.

rosijanka [135]

$\bf \qquad \textit{Quad identities}\\\\
sin(4\theta )=
\begin{cases}
8sin(\theta )cos^3(\theta )-4sin(\theta )cos(\theta )\\
4sin(\theta )cos(\theta )-8sin^3(\theta )cos(\theta )
\end{cases}
\\\\\\
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-------------------------------\\\\
9cos(4x)\implies 9[8cos^4(x)-8cos^2(x)+1]
\\\\\\
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---------------------------------------------------------------------------

as far as the previous one on the 2tan(3x)

$\bf tan(2\theta)=\cfrac{2tan(\theta)}{1-tan^2(\theta)}\qquad tan({{ \alpha}} + {{ \beta}}) = \cfrac{tan({{ \alpha}})+ tan({{ \beta}})}{1- tan({{ \alpha}})tan({{ \beta}})}\\\\
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$\bf 2tan(3x)\implies 2tan(2x+x)\implies 2\left[ \cfrac{tan(2x)+tan(x)}{1-tan(2x)tan(x)}\right]
\\\\\\
2\left[ \cfrac{\frac{2tan(x)}{1-tan^2(x)}+tan(x)}{1-\frac{2tan(x)}{1-tan^2(x)}tan(x)}\right]\implies 2\left[ \cfrac{\frac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}}{\frac{1-tan(x)-2tan^3(x)}{1-tan^2(x)}} \right]
\\\\\\$

$\bf 2\left[ \cfrac{2tan(x)+tan(x)-tan^3(x)}{1-tan^2(x)}\cdot \cfrac{1-tan^2(x)}{1-tan(x)-2tan^3(x)} \right]
\\\\\\
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3 years ago

The measure of angle 4 is 45. If angle 4 is congruent to angle 1, what is the measure of angle 5?

mr_godi [17]

The answer is A) 45°. This is because angles 1 and 5 are vertical angles. Vertical angles are congruent.

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3 years ago

In ADEF, m must be true?<br> Plssss need helpppp

Rzqust [24]

Answer:

E. FD<DE<EF

Step-by-step explanation:

First I needed to find the other angle which I found by adding the two angles that were given.

103 +14 =117

180 - 117= 63

then to find which sides were the longest I looked and the angles and found their corresponding sides.

<D went with side FE

<F went with side DE

<E went with side FD

The smallest angle was <E therefore the smallest side was FD

The middle angle was <F therefore the medium side was DE

The largest angle was <D therefore the smallest side was FE

I hope this helps!!

Please tell me if I have made a mistake enjoy learning from them!!

If I am correct could you please mark me brainliset? I am trying to level up!!

Thank you for your time:)

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natta225 [31]

Answer:43?

Step-by-step explanation:

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3 years ago