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2 years ago

How could Sam determine the distance he drove and the true displacement between the two locations

1 answer:

5 0

Distance is the physical length travelled. While the displacement is the shorter distance between any two given points.

<h3>What is distance?</h3>

Distance is a numerical representation of the distance between two objects or locations.

Distance can refer to a physical length or an estimate based on other factors in physics or common use. |AB| is a symbol for the distance between two points A and B.

Displacement is defined as the shortest distance between the two points.

Sam determines the distance by doing the calculation as;

distance = speed × time

Hence, the Sam determines the distance and displacement by the respective formulas.

To learn more about the distance, refer to the link;

brainly.com/question/26711747

#SPJ1

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Describe how the wavelength of a wave changes if the wave slows down but its frequency does not change.

babunello [35]

Answer:

If the wave slows down with no change in frequency, the wavelength decreases.

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3 years ago

Mass is a fundamental physical quantity give scientific reason

Lena [83]

Answer:

yes

Explanation:

because it is independent of eachother

8 0

2 years ago

Scientists are working on a new technique to kill cancer cells by zapping them with ultrahigh-energy (in the range of 1012 W) pu

Tcecarenko [31]

1. $7.95\cdot 10^6 J$

The total energy given to the cells during one pulse is given by:

$E=Pt$

where

P is the average power of the pulse

t is the duration of the pulse

In this problem,

$P=1.59\cdot 10^{12}W$

$t=5.0 ns = 5.0\cdot 10^{-9} s$

Substituting,

$E=(1.59\cdot 10^{12}W)(5.0 \cdot 10^{-6}s)=7.95\cdot 10^6 J$

2. $1.26\cdot 10^{21}W/m^2$

The energy found at point (1) is the energy delivered to 100 cells. The radius of each cell is

$r=\frac{4.0\mu m}{2}=2.0 \mu m = 2.0\cdot 10^{-6}m$

So the area of each cell is

$A=\pi r^2 = \pi (2.0 \cdot 10^{-6}m)^2=1.26\cdot 10^{-11} m^2$

The energy is spread over 100 cells, so the total area of the cells is

$A=100 (1.26\cdot 10^{-11} m^2)=1.26\cdot 10^{-9} m^2$

And so the intensity delivered is

$I=\frac{P}{A}=\frac{1.59\cdot 10^{12}W}{1.26\cdot 10^{-9} m^2}=1.26\cdot 10^{21}W/m^2$

3. $9.74\cdot 10^{11} V/m$

The average intensity of an electromagnetic wave is related to the maximum value of the electric field by

$I=\frac{1}{2}c\epsilon_0 E^2$

where

c is the speed of light

$\epsilon_0$ is the vacuum permittivity

E is the amplitude of the electric field

Solving the formula for E, we find:

$E=\sqrt{\frac{2I}{c\epsilon_0}}=\sqrt{\frac{2(1.26\cdot 10^{21} W/m^2)}{(3\cdot 10^8 m/s)(8.85\cdot 10^{-12}F/m)}}=9.74\cdot 10^{11} V/m$

4. 3247 T

The magnetic field amplitude is related to the electric field amplitude by

$E=cB$

where

E is the electric field amplitude

c is the speed of light

B is the magnetic field

Solving the equation for B and substituting the value of E that we found at point 3, we find

$B=\frac{E}{c}=\frac{9.74\cdot 10^{11} V/m}{3\cdot 10^8 m/s}=3247 T$

3 0

3 years ago

What percentage of the power of the battery is dissipated across the internal resistance and hence is not available to the bulb?

spin [16.1K]

Lets us consider an example:

Suppose a 10 ohm bulb is connected across the terminals of a 10 V

battery having 2ohm internal resistance.

Then total reistance in series we know, R1 + R2

Thus, R net = 10+ 2 = 12 ohm

The, current across circuit = 10/12= 0.833 A

Now, Power is given by $P = i^{2} R \\ \\$

Thus, power dissipated across internal resistance, P = $0.83^{2} * 2 = 1.37 Watt$

And, total power dissipated = $0.83^{2} * 12 = 8.2 watt$

Thsu, percentage of pwer not avaible = 1.37/8.2 = 16.70%

5 0

4 years ago

lock of mass m2 is attached to a spring of force constant k and m1 . m2. If the system is released from rest, and the spring is

patriot [66]

Answer:

The maximum displacement of the mass m₂ $= \frac{2(m_1-m_2)g}{k}$

Explanation:

Kinetic Energy (K) = 1/2mv²

Potential Energy (P) = mgh

Law of Conservation of energy states that total energy of the system remains constant.

i.e; Total energy before collision = Total energy after collision

This implies that: the gravitational potential energy lost by m₁ must be equal to sum of gravitational energy gained by m₂ and the elastic potential energy stored in the spring.

$m_1gd = m_2gd+\frac{1}{2}kd^2\\\\m_1g = m_2g+\frac{1}{2}kd\\\\d = \frac{2(m_1-m_2)g}{k}$

d = maximum displacement of the mass m₂

7 0

4 years ago