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3 years ago

What must be attached to each carburetor on a gasoline inboard engine?

1 answer:

3 0

To each carburetor on a gasoline inboard engine a backfire flame arrestor must be attached.This arrestor will prevent flames from the backfire causing a fire on board. Several things are important in order the backfire arrestor to function properly:
- should be clean and undamaged.
- If there is a hole in the grid, or oil or gasoline in the grid, or if it is not properly attached, the arrestor will not work correctly.
- must be approved by the U.S. Coast Guard

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A block of wood has density 0.500 g/cm3 and mass 2 000 g. It floats in a container of oil (the oil's density is 0.750 g/cm3). Wh

Gennadij [26K]

Answer:

2,666.67cm^3

Explanation:

All we need to do in this problem is divide the mass of the wooden block to the oil's density.

2000/0.750 ≈ 2,666.67cm^3

Best of Luck!

6 0

2 years ago

I dont get why its c i dont under the graph for the vertical component in option c

jek_recluse [69]

The vertical component grows at an increasing rate because
gravity is ACCELERATING the object vertically. So its speed
keeps growing. Speed is the slope of the displacement graph.

7 0

3 years ago

A block is at rest on a plank whose angle can be varied. The angle is gradually increased from 0 deg. At 31.8°, the block starts

galina1969 [7]

Answer:

$\mu_s = 0.62$

$\mu_k = 0.415$

The motion of the block is downwards with acceleration 1.7 m/s^2.

Explanation:

First, we will calculate the acceleration using the kinematics equations. We will denote the direction along the incline as x-direction.

$x - x_0 = v_0t + \frac{1}{2}at^2\\3.4 = 0 + \frac{1}{2}a(2)^2\\a = 1.7~m/s^2$

Newton’s Second Law can be used to find the net force applied on the block in the -x-direction.

$F = ma\\F = 1.7m$

Now, let’s investigate the free-body diagram of the block.

Along the x-direction, there are two forces: The x-component of the block’s weight and the kinetic friction force. Therefore,

$F = mg\sin(\theta) - \mu_k mg\cos(\theta)\\1.7m = mg\sin(31.8) - \mu_k mg\cos(31.8)\\1.7 = (9.8)\sin(\theta) - mu_k(9.8)\cos(\theta)\\mu_k = 0.415$

As for the static friction, we will consider the angle 31.8, but just before the block starts the move.

$mg\sin(31.8) = \mu_s mg\cos(31.8)\\\mu_s = tan(31.8) = 0.62$

5 0

3 years ago

how much voltage is in the primary coil if there are 3200 winding in the secondary coil 500 winding in the primary and 25v in th

Tema [17]

Answer:

Voltage in the primary winding of the coil is 3.9 V

Explanation:

As we know by the principle of transformer we have

$\frac{V_s}{V_p} = \frac{N_s}{N_p}$

here we know that

$V_s = 25 volts$

$N_s = 3200$

$N_p = 500$

now we have

$\frac{25}{V_p} = \frac{3200}{500}$

$V_p = 3.9 Volts$

7 0

3 years ago

These plans are an accompaniment to mechanical lifting devices in reducing on-the-job injuries. they address specific patient ne

lilavasa [31]

For the answer to the question, ergonomics is the science of fitting the job to the worker. When there is a mismatch between the physical requirements of the job and the physical capacity of the worker, work-related musculoskeletal disorders (MSDs) can result. Ergonomics is the practice of designing equipment and work tasks to conform to the capability of the worker, it provides a means for adjusting the work environment and work practices to prevent injuries before they occur.

4 0

3 years ago