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Zielflug [23.3K]
3 years ago
5

At a certain instant an object is moving to the right with speed 1.0 m/s and has a constant acceleration to the left of 1.0 m/s2

. At what later time will the object momen- tarily be at rest?
Physics
1 answer:
professor190 [17]3 years ago
5 0

Explanation:

Given that,

Initial speed of the object, u = 1 m/s

Acceleration of the object, a=-1\ m/s^2

We need to find the time when the object comes at rest (v=0). Let it is given by :

t=\dfrac{v-u}{a}

t=\dfrac{0-1\ m/s}{-1\ m/s^2}

t = 1 second

So, the object will comes to rest at 1 second. Hence, this is the required solution.

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A tall cylinder contains 30 cm of water. Oil is carefully poured into the cylinder, where it floats on top of the water, until t
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From the question we are told that

       The height of the water contained is  h_w  =  30 \ cm  =  0.3 \ m

        The height of liquid in the cylinder is  h_t  =  40 \ cm  = 0.4 \ m

       

At the bottom of the cylinder the gauge pressure is  mathematically represented as

        P_g  =  P_w + P_o

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   substituting values

      P_w  = 1000 *  9.8 *  0.3

     P_w  =  2940 \  Pa

While P_o is the pressure of oil which is mathematically represented as

          P_o  =  \rho_o *  g *  (h_t -h_w )

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       P_o  =  900 *  9.8 * (0.4 - 0.3)

       P_o  =  882 \ Pa

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      P_g  =  2940 - 882

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