A string with linear density 0.500 g/m.
Tension 20.0 N.
The maximum speed 
The energy contained in a section of string 3.00 m long as a function of
.
We are given following data for string with linear density held under tension :
μ = 0.5 
= 0.5 x 10⁻³ 
T = 20 N
If string is L = 3m long, total energy as a function of
is given by:
E = 1/2 x μ x L x ω² x A²
= 1/2 x μ x L x 
= 7.5 x 10⁻⁴ 
So, The total energy as a function of
= 7.5 x 10⁻⁴ 
Learn more about linear density problem here:
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Answer:
When elements bond together or when bonds of compounds are broken and form a new substance
Explanation:
Answer:
Torque on the coil will be ZERO
Explanation:
As we know that the magnetic moment of the closed current carrying coil is always along its axis and it is given as

now we know that magnetic field is also along the axis of the coil so here as we know the equation of torque given as

so we have


Answer:
<em>709.5 cal</em>
<em></em>
Explanation:
masa m de la barra de aluminio = 100 g
temperatura ambiente = 27 ° C
<em>Asumiremos que la barra de aluminio está en equilibrio térmico con el ambiente.
</em>
Esto significa que la temperatura inicial de la barra es de 27 ° C
temperatura final a la que la barra debe calentarse = 60 ° C
el aumento de temperatura ΔT será
ΔT = 60 ° C - 27 ° C = 33 ° C
capacidad calorífica específica c del aluminio = 0.215 cal/g°C
Calor C requerido = mcΔT
<em>C = 100 x 0.215 x 33 = 709.5 cal</em>