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umka2103 [35]
3 years ago
6

PLS ANSWER FAST THIS IS TIMED TEST AND WILL GIVE BRAINLY!!!

Physics
1 answer:
mylen [45]3 years ago
6 0

Answer:

mass is 5 kg

Explanation:

F=m/a

M=f/a

F=5000

a=1000

5000/1000=5

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PLEASE HELPPPPP!!!! :)
GuDViN [60]

Answer:

F=X.F=mxq. 3. 1 N/kg=0.5kg g=9.80

4 0
2 years ago
The main difference between turbojets and rocket engines is the fact that
mafiozo [28]

Answer;

D. rocket engines are not dependent on oxygen from the air.

Explanation;

-Jet engines and rockets work on the same principle. They produce thrust through an internal pressure difference and, as explained by Newton’s Third Law of Motion, eject exhaust gases in an equal and opposite direction.

-The main difference between them is that jets get the oxygen to burn fuel from the air and rockets carry their own oxygen, which allows them to operate in space.

Additionally, Jet engines have two openings (an intake and an exhaust nozzle). Rocket engines only have one opening (an exhaust nozzle).

5 0
3 years ago
Read 2 more answers
Materials that are soft and porous will absorb energy causing a decrease in amplitude and energy of the sound. This is called __
Vedmedyk [2.9K]
Damping of the sound
5 0
2 years ago
Rank the tensions in the ropes, t1, t2, and t3, from smallest to largest, when the boxes are in motion and there is no friction
gizmo_the_mogwai [7]
<span>AS T1,T2,T3 are the tensions in the ropes,assuming that there are Three blocks of mass 3m, 2m, and m.T3 is the string between 3m and 2m,T2 is the string between 2m and m ,T1 is the string attached to m thus T1 pulls the whole set of blocks along, so it must be the largest. T2 pulls the last two masses, but T3 only pulls the last mass, so T3 < T2 < T1.</span>
5 0
3 years ago
2. A particular planet has a moment of inertia of 9.74 × 1037 kg•m2 and a mass of 5.98 × 1024 kg. Based on these values, what is
mash [69]

Answer:

6.38\cdot 10^6 m

Explanation:

The planet can be thought as a solid sphere rotating around its axis. The moment of inertia of a solid sphere rotating arount the axis is

I=\frac{2}{5}MR^2

where

M is the mass

R is the radius

For the planet in the problem, we have

M=5.98\cdot 10^{24} kg

I=9.74\cdot 10^{37} kg\cdot m^2

Solving the equation for R, we find the radius of the planet:

R=\sqrt{\frac{5I}{2M}}=\sqrt{\frac{5(9.74\cdot 10^{37}}{2(5.98\cdot 10^{24}}}=6.38\cdot 10^6 m

3 0
3 years ago
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