Question

W7L5 Stoichiometry Practice 2

Answer 1

Answer:

.079 moles of Nirogen gas (N2)

Explanation:

You can see from the equaton that each ONE mole of N2 produces TWO moles of NH3.

 Find the number of moles of NH3 produced.

    Using Periodic Table : Mole wt of NH3 = 17 gm/mole

          2.7 gm / 17 gm/mole = .1588 moles

      One half as many moles of N2 are needed  = .079 moles