Seems correct. Your steps make sense, the molar ratios are right and you've done it in a clear easy to follow manner. I see no issues with it.
Elements occur naturally in different forms called isotopes. These are the same atoms with the same number of protons but has different number of neutrons. Almost all elements exist in nature as such. The amounts of these isotopes are expressed in terms of percent abundances and since it is in a percentage units, the sum of all the abundances should equate to 100 percent or else the calculation is wrong. This is not true onlt for magnesiun but with all of the elements. The atomic mass of these elements also depends on the percent abundances of the isotopes since it is a weighted average value of the individual masses of the isotopes.
B.) Heterogeneous
The prefix homo is referred to meaning the same or equal
Answer:
C. 64
Explanation:
Given:
The number of equally likely sample outcomes of a single stage = 4
Unknown:
Total number of elements if there are three stages= ?
Solution;
Probability is the likelihood of an event to occur.
In this problem;
For a single stage, the likely outcome is 4
So therefore;
For the 3 stages 4 x 4 x 4 = 64
Therefore, the total number of elements in the sample space of an experiment with 3 stages is 64
Answer:
8.08 × 10⁻⁴
Explanation:
Let's consider the following reaction.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
The initial concentration of phosgene is:
M = 2.00 mol / 1.00 L = 2.00 M
We can find the final concentrations using an ICE chart.
COCl₂(g) ⇄ CO (g) + Cl₂(g)
I 2.00 0 0
C -x +x +x
E 2.00 -x x x
The equilibrium concentration of Cl₂, x, is 0.0398 mol / 1.00 L = 0.0398 M.
The concentrations at equilibrium are:
[COCl₂] = 2.00 -x = 1.96 M
[CO] = [Cl₂] = 0.0398 M
The equilibrium constant (Keq) is:
Keq = [CO].[Cl₂]/[COCl₂]
Keq = (0.0398)²/1.96
Keq = 8.08 × 10⁻⁴
