Answer: 8.57 ml of KOH is required to reach the equivalence point.
Explanation:
To calculate the volume of acid, we use the equation given by neutralization reaction:
where,
are the n-factor, molarity and volume of acid which is 
are the n-factor, molarity and volume of base which is KOH.
We are given:
Putting values in above equation, we get:
Thus 8.57 ml of KOH is required to reach the equivalence point.
Volume of O2 : 168 L
<h3>Further explanation</h3>
Given
Reaction
2 KClO3 (s) → 2 KCl (s) + 3 O2 (g)
5 moles of KCIO3
Required
volume of O2
Solution
From the equation, mol O2 :
= 3/2 x moles KClO3
= 3/2 x 5 moles
= 7.5 moles
Assumed at STP( 1 mol = 22.4 L) :
= 7.5 x 22.4 L
= 168 L
Answer:
Check the explanation below
Explanation:
Stream - a series of connected channels that fills with water
Tributary - one of many channels that connect to form a river
Gully - a channel of connected grooves created by runoff
Rill - a small groove in soil created by runoff
Answer:
a way in which something is usually done, especially within a particular area or activity.
Explanation:
Answer:
The answer is "Each student will get a glass of water and drop the bead into it but the beads float 0.6 g / cm3 and slip down to 1.2 g / cm3
".
Explanation:
One's masses would've been dissimilar, even though their width and concentrations were also equal. Whenever the type-A mass is m, then the type-B mass is 2 m. One should measure then, therefore.
Water has a 1g / cm^3 density. Although Type A is higher than air, Type B is much more compact. it means will float if they place it in water type-A where type-B sinks.
