Answer:
The new temperature of the water bath 32.0°C.
Explanation:
Mass of water in water bath ,m= 8.10 kg = 8100 g ( 1kg = 1000g)
Initial temperature of the water = 
Final temperature of the water = 
Specific heat capacity of water under these conditions = c = 4.18 J/gK
Amount of energy lost by water = -Q = -69.0 kJ = -69.0 × 1000 J
( 1kJ=1000 J)
The new temperature of the water bath 32.0°C.
5.451 X 10³ kg of sodium carbonate must be added to neutralize 5.04×103 kg of sulfuric acid solution.
<u>Explanation</u>:
- Sodium carbonate is used to neutralized sulfuric acid, H₂SO₄. Sodium carbonate is the salt of a strong base (NaOH) and weak acid (H₂CO₃). The balanced chemical reaction for neutralization is as follows:
Na₂CO₃ + H₂SO₄ ----> Na₂SO₄ + H₂CO₃
- From a balanced chemical equation, it is clear that one mole of Na₂CO₃ is required to neutralize one mole of H₂SO₄.
- Molar mass of Na₂CO₃= 106 g/mol = 0.106 kg/mol and Molar mass of H₂SO₄= 98 g/mol = 0.098 kg/mol.
- To neutralize 0.098 kg of H₂SO₄ amount of Na₂CO₃ required is 0.106 kg, so, To neutralize 5.04×10³ kg of H₂SO₄, Na₂CO₃ required is = 5.451 X 10³ kg.
First, we have to start balancing the equation:
H2O2 + FeSO4 + H2SO4 → Fe2(SO4)3 + H2O
we can see that the number of H atoms on the left side is 4 and on the right side is 2 so we have to make the number of H atoms are equal on both sides
so, we will put 2H2O instead of H2O
H2O2 + FeSO4 + H2SO4 → Fe2(SO4)3 + 2H2O
we can see that number of O on the left side is 10 and on the right side 14
so we will put 2 FeSO4 instead of FeSO4
H2O2 + 2FeSO4 + H2SO4 → →Fe2(SO4)3 + 2H2O
∴ the coefficients of the reactants and products will be in order 1 2 1 1 2
I think so. Half of 90 is 45 so 45 divided by 3 (3 seconds) if 15. 15 meters per second.
