Answer:
78
Explanation:
atomic number is number of protons
Answer:
Explanation:
<u>1) Arrhenius equation</u>
Arrhenius equation shows the relation between activation energy, temperature, and the equilibrium constant.
This is the equation:
Where:
- K is the equilibrium constant,
- A is the frequency factor,
- Ea is the activation energy (in J/mol),
- T is the temperature in kelvins (K), and
- R is the universal constant.
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<u>2) Substitute, using the right units, and compute:</u>
- A = 4.20 × 10¹² (dimensionless)
- Ea = 67.0 kJ/mol = 67,000 J/mol
- T = 24.0°C = 24.0 + 273.15 K = 297.15 K
- R = 8.314 J/K mol
The question is incomplete. The complete question is
In the molecule on the left, areas that have a partial negative charge are pink and areas that have a partial positive charge are blue. The molecule on the right is nonpolar.
What will most likely happen when these molecules get closer?
The molecules will repel each other because of a dipole-dipole interaction. The molecules will attract each other because of a dipole-dipole interaction. An induced dipole will be produced in the molecule on the right. An induced dipole will be produced in the molecule on the left.
Answer:
An induced dipole will be produced in the molecule on the right.
Explanation:
The molecule on the left already possesses a dipole. A dipole means the presence of a negative end and a positive end in a molecule.
Hence when the other molecule approaches, the polarized molecule induces a dipole on it. This second kind of dipole is known as 'induced dipole' hence the answer.
SO2 is a polar molecule because Oxygen gains more electrons making one side more negative than the other.
We are tasked to find the amount of O2 in grams given only the number of moles of oxygen gas. To solve the problem, we need first to calculate the molecular weight of oxygen. Based on the periodic table, elemental oxygen has a molecular weight of 16 g/mol. Thus its molecular weight is,
O2=16.0g/mol (2)=32 g/mol
To solve for the amount of compound oxygen in grams, we have,
O2 (g)=5 mol x 32 g/mol =160 g.
This cancel out the mols both in the numerator and denominator leaving only the g as a unit. Therefore, 5 mols of oxygen is equal to 160 g of oxygen.
