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Pani-rosa [81]
3 years ago
11

How many moles of ions are produced by the dissociation of 0.5 mol of na2co3?

Chemistry
2 answers:
tatiyna3 years ago
5 0
The number of moles of ions that   are produced  by  the dissociation  of  o.5 mol  of Na2CO3  is   1.5  moles


    Explanation
 write the  equation  for dissociation  of  Na2CO3
that is Na2Co3 →  2Na^+(aq)  +  CO3^2- (aq)

by  use of mole ratio  of Na2CO3 to Na^+ and to  CO3^2-   which is 1:2:1  the  moles of  Na^+ =  0.5  x2 =  1mole
the  moles of CO3^2-  =  0.5  x1  = 0.5 moles


total  moles = moles  of CO^2-     +   moles  of  Na^+

that   is  1 mole + 0.5 mole =  1..5  moles
Alexus [3.1K]3 years ago
3 0

Answer:

1.5 mol ions

Explanation:

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GarryVolchara [31]

Answer:

The value of the Golden Igloo is $227.4 million.

Explanation:

First, we need to find the inner and the outer volume of the half-spherical shell:

V_{i} = \frac{1}{2}*\frac{4}{3}\pi r_{i}^{3}

V_{o} = \frac{1}{2}*\frac{4}{3}\pi r_{o}^{3}

The total volume is given by:

V_{T} = V_{o} - V_{i}

Where:

V_{i}: is the inner volume

r_{i}: is the inner radius = 1.25/2 = 0.625 m

V_{o}: is the outer volume

r_{o}: is the outer radius = 1.45/2 = 0.725 m

Then, the total volume of the Igloo is:

V_{T} = \frac{2}{3}\pi r_{o}^{3} - \frac{2}{3}\pi r_{i}^{3} = \frac{2}{3}\pi [(0.725 m)^{3} - (0.625 m)^{3}] = 0.29 m^{3}

Now, by using the density we can find the mass of the Igloo:

m = 19.3 \frac{g}{cm^{3}}*0.29 m^{3}*\frac{(100 cm)^{3}}{1 m^{3}} = 5.60 \cdot 10^{6} g

Finally, the value (V) of the antiquity is:

V = \frac{\$ 1263}{oz}*5.60 \cdot 10^{6} g*\frac{1 oz}{31.1034768 g} = \$ 227.4 \cdot 10^{6}  

Therefore, the value of the Golden Igloo is $227.4 million.

I hope it helps you!  

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2 years ago
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<h3>Bond</h3>

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