Answer:
16.5moles of CO2
Explanation:
Molar mass of O2 is 32g/Mol
No of mole = 880/32 = 27.5 moles
27.5 Mol of O2 gives X mole of CO2
5 mole of O2 gives 3 moles of CO2
No of mole of CO2 = (27.5×3)/ 5 = 16.5moles
The mass of a present which has a density of 2.15 kg/L and volume of 3650 mL is 7.74 kg.
<h3>How do we calculate mass?</h3>
Mass of any substance will be calculate by using the density and volume by using the below equation as:
Density = Mass / Volume
Given that,
Density of Christmas present = 2.15 kg/L
Volume of present = 3,650 mL = 3.6L
On putting values, we get
Mass = (2.15)(3.6) = 7.74
Hence required mass of Christmas present is 7.74 kg.
To know more about density, visit the below link:
brainly.com/question/10441359
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I had this exact question on my chemistry test PETE used in water bottles
HDPE used in expensive water bottles
LDPE use in cheap waterbottles
i put this on my test and get it all right
Answer:
By reacting carbon monoxide and hydrogen the formation of methanol takes place, the reaction is,
CO(g)+2H₂(g)⇔CH₃OH (g)
Based on the given reaction, one mole of methanol is obtained by reacting one mole of carbon monoxide (CO) with the two moles of hydrogen (H₂). It is mentioned in the question that for the reaction 500 mol of carbon monoxide and 750 moles of hydrogen are present.
Therefore for 500 moles of carbon monoxide, there is a requirement of 2 × 500 moles of hydrogen, which is equivalent to 1000 moles of hydrogen (H₂). However, only 750 moles of hydrogen is present. Therefore, the limiting reactant in the given case is H₂. The present moles of H₂ will react with 0.5 × 750 moles of CO = 375 mole of CO
The additional or excess concentration of CO, which is the excess reactant will be, 500-375 = 125 moles.
