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QveST [7]
3 years ago
12

For the graphed function f(x) = (4)x − 1 + 2, calculate the average rate of change from x = 1 to x = 2.

Mathematics
2 answers:
marissa [1.9K]3 years ago
6 0

Answer:

Option B is correct.

Average rate of change from x=1 to x=2 is 3

Step-by-step explanation:

Formula for Average rate of change: The ratio of the difference in the  function f(x) as it changes from a to b to the difference between a and b :

A(x) = \frac{f(b)-f(a)}{b-a}

As per the statement:

f(x) = 4^{x-1} +2

Calculate the average rate of change from x =1 to x =2

At x = 1

f(1) = 4^{1-1} +2 = 1 +2 = 3

At x = 2

f(2) = 4^{2-1} +2 = 4^1 +2 = 4+2 =6

Then;

A(x) = \frac{f(2)-f(1)}{2-1} = \frac{6-3}{1} =\frac{3}{1} = 3

Therefore, the average rate of change from x=1 to x=2 is 3


xz_007 [3.2K]3 years ago
3 0
For the function
  f(x) = 4^(x-1) +2
the average rate of change on the interval [1, 2] is found by computing
  (f(2) - f(1))/(2 - 1)
  = ((4^1+2) - (4^0+2)/1
  = (6-3)
  = 3
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Factorise x+y<br><br>-ax-ay​
mariarad [96]

Answer:

(x + y)1 - a)

Step-by-step explanation:

x + y - ax - ay

= x - ax + y - ay

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3 years ago
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Need help please ! parallelogram
OverLord2011 [107]

Answer:

11). m∠W = 70°

12). m∠M = 95°

13). m∠Q = 135°

14). m∠Q = 55°

15). m∠X = 110°

Step-by-step explanation:

11). m∠W + m∠X = 180° [Consecutive interior angles]

    (24x - 2) + (36x + 2) = 180°

     60x = 180°

     x = \frac{180}{60}

     x = 3

     Therefore, m∠W = (24x - 2)°

     m∠W = (24×3 - 2)

               = 72 - 2

               = 70°

     Since opposite angles of a parallelogram are equal in measure.

     m∠Y = m∠W = 70°

12). m∠J + m∠K = 180° [Consecutive interior angles]

     (6x + 19) + (8x + 7) = 180°

     14x + 26 = 180

     14x = 180 - 26

     14x = 154

     x = \frac{154}{14}

     x = 11

     m∠K = (8x + 7)

     m∠K = 8×11 + 7

     m∠K = 95°

     Since m∠M = m∠K

     Therefore, m∠M = 95°

13). m∠Q = m∠S [Opposite angles of a parallelogram]

      x + 135 = 2x + 135

      2x - x = 0

      x = 0

      Therefore, m∠Q = 135°

14). m∠Q = m∠S [Opposite angles of a parallelogram]

      14x - 1 = 13x + 3

      14x - 13x = 3 + 1

      x = 4

      m∠Q = (13x + 3)

                = 13×4 + 3

                = 52 + 3

      m∠Q = 55°

15). m∠Z = m∠X

     (19x - 4) = (17x + 8)

      19x - 17x = 12

      2x = 12

      x = 6

      m∠X = (17x + 8)°

      m∠X = 17×6 + 8

      m∠X = 110°

5 0
3 years ago
Find the surface area of a pyramid with a square base with dimensions 100 mm by 100 mm and height of 75 mm.
Reil [10]

To solve for the surface area of the pyramid, we make use of the formula:

A= l w + l [sqrt ((w / 2)^2 + h^2)] + w [sqrt ((l / 2)^2 + h^2))

where,

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h is the height of the pyramid = 75 mm

 

Substituting the given values into the equation:

A= 100 * 100 + 100 [sqrt ((100 / 2)^2 + 75^2)] + 100 [sqrt ((100 / 2)^2 + 75^2))

A = 10,000 + 100 (sqrt 2575) + 100 (sqrt 2575)

A = 20,148.90 mm^2

 

Therefore the surface area of the pyramid is about 20,149 mm^2.

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