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alukav5142 [94]
3 years ago
15

GEOMETRY HELP PLEASE!! WILL MARK BRAINLEIST! 5

Mathematics
2 answers:
adell [148]3 years ago
5 0

AC=BD

64 units=10x+24

64-24=10x

40=10x

X=40 divided by 10= 4

hope it helps:)))

vichka [17]3 years ago
3 0
X=4 you subtract 64 by 24 and then divide that by 10 and that equals X
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The height of a parallelogram is one-third its base. If the area of the parallelogram is 363 square inches, find its base and he
kipiarov [429]

Answer:

Height = 11 inches

Base = 33 inches

Step-by-step explanation:

In this question, we are asked to find the height and base of a parallelogram given the area of the parallelogram.

From the question, we are told that height is 1/3 of base. This means that base is 3 times the height

So if we represent the height with variable h, then the base is 3h

Mathematically the area of a parallelogram can be calculated by the formula

A = bh

Thus ,

363 = h * 3h

3h^2 = 363

divide through by 3

h^2 = 121

h = √121

h = 11 inches

since b = 3h , then b = 3 * 11 = 33 inches

8 0
3 years ago
Determine the domain of the function h=9x/x(x^2-49)
Juliette [100K]

ANSWER

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

EXPLANATION

The given function is

h(x) =  \frac{9x}{x( {x}^{2} - 49) }

This function is defined for values where the denominator is not equal to zero.

x( {x}^{2}  - 49) \ne0

x(x - 7)(x + 7) = 0

The domain is

x \ne - 7, x \ne0, \: and \:  x \ne 7,

Or

( -  \infty , - 7) \cup( - 7 , 0) \cup(0 , 7 )\cup(7 , +   \infty )

8 0
3 years ago
Is there a relationship between the area and the perimete of a rectangle. Explain
Nady [450]
The area is another way of say perimeter. it's the inside area of the rectangle
5 0
3 years ago
Can anyone answer this problem in their head. No calculator or paper.
rodikova [14]
7,393,420,225 is the answer tk the problem without using calculator.
7 0
3 years ago
How do you solve U/6=9
notsponge [240]
/ means divide, so U( an unknown value ) / 6 = 9. to get the answer, simply multiply  6 x 9 
6 0
3 years ago
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