a)CH3-CH2-CH2-CH=CH2
b)CH3-CH2-CH2-CH2-CH2-CH2-CH3
c)CH≡C-CH2-CH2-CH2-CH3
d)CH3-CH2-CH2-CH2-CH2-CH2-CH=CH2
e)CH3-CH2-CH2-CH2-CH2-CH2-CH2-CH2-CH3
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The pressure of the gas is 1.0 bar.
<em>pV</em> = <em>nRT</em>
<em>T</em> = (0 + 273.15) K = 273.15 K
<em>p</em> = (<em>nRT</em>)/<em>V</em> = (2.0 mol × 0.083 14 bar·L·K⁻¹mol⁻¹ × 273.15 K)/44.8 L = 1.0 bar