Answer:
2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)
Explanation:
The balanced equation for the reaction between butane and oxygen to produce carbon dioxide and water can be written as follow:
C₄H₁₀ + O₂ —> CO₂ + H₂O
Next, we shall balanced the equation. This is illustrated below:
C₄H₁₀ + O₂ —> CO₂ + H₂O
There are 4 atoms of C on the left side and 1 atom on the right side. It can be balance by writing 4 before CO₂ as shown below:
C₄H₁₀ + O₂ —> 4CO₂ + H₂O
There are 10 atoms of H on the left side and 2 atoms on the right side. It can be balance by writing 5 before H₂O as shown below:
C₄H₁₀ + O₂ —> 4CO₂ + 5H₂O
There are 2 atoms of O on the left side and a total of 13 atoms on the right side. It can be balance by writing 13/2 before O₂ as shown below:
C₄H₁₀ + 13/2O₂ —> 4CO₂ + 5H₂O
Multiply through by 2 to express in whole number ratio.
2C₄H₁₀(g) + 13O₂(g) —> 8CO₂(g) + 10H₂O(g)
Thus, the equation is balanced.
Answer: A
Explanation: Im pretty sure it's A, if you're desperate, go ahead and take my advice. If you're not you probably shouldnt.
I'm going to put it in chat.Hope this help.
Answer: D : A is 3 : 2.
Explanation:
The law of definite proportion is being used here. The law states that a given compound always has the same proportion of its constituent elements by mass.
2a + b = c + 3d
This actually means that, two moles of “a” react with a mole of “b” to produce a mole of “c” and 3 moles of “d”
Using the concept of stoichiometry coefficients of d and a
d:a = 3:2
Wouldn't it be 100? 150 - 50 would equal 100. Unless I'm not seeing something.