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worty [1.4K]
3 years ago
12

117 milligrams (mg) of purified product was isolated from a chemical reaction. This experimental yield of product represents a 8

9.0% yield for the reaction. Calculate the theoretical yield, in milligrams (mg), for this reaction. Enter your answer as digits only, no units, using the proper number of significant figures.
Chemistry
1 answer:
Brut [27]3 years ago
5 0

Answer:

131 mg

Explanation:

Percent yield = 89%

Actual yield = 117 mg

Percent yield is given by

\text{Percent yield}=\dfrac{\text{Actual yield}}{\text{Theoretical yield}}\times 100\\\Rightarrow 89=\dfrac{117}{\text{Theoretical yield}}\times 100\\\Rightarrow \text{Theoretical yield}=\dfrac{117}{89}\times 100\\\Rightarrow \text{Theoretical yield}=131.46\approx 131\ \text{mg}

The theoretical yield, for this reaction is 131 mg.

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Define Evaporation.<br>Thanks​
Kay [80]

Answer:

evapouration is a type of vaporization that occur on the surface of liquid as it change into the gas phase.

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3 years ago
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If 45.0 mL of a 0.0500 M HNO3, 10.0 mL of a 0.0500 M KSCN, and 30.0 mL of a 0.0500 M Fe(NO3)3 are combined, what is the initial
jeka94

Answer:

the  initial concentration of SCN- in the mixture is 0.00588 M

Explanation:

The computation of the initial concentration of the SCN^- in the mixture is as follows:

As we know that

KSCN \rightarrow K^ + SCN^-

As it is mentioned in the question that KSCN is present 10 mL of 0.05 M

So, the total milimoles of SCN^- is

= 10 × 0.05

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The total volume in mixture is

= 45 + 10 + 30

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Now the initial concentration of the SCN^- is

= 0.5 ÷ 85

= 0.00588 M

hence, the  initial concentration of SCN- in the mixture is 0.00588 M

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3 years ago
Which of the following is not a way populations are described?​
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The last answer

the place where the organisms live

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2 years ago
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What is the ionic charge for C, Si, Ge, Sn and Pb?
Alecsey [184]
An atom of carbon has 4 electrons in its outermost shell, which means that 
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6 0
3 years ago
Use MO diagrams to place B2+, B2, and B2- in order of (a) decreasing bond energy; (b) decreasing bond length.
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We use the MO diagram for a homonuclear diatomic species (since C and N are neighbours, we treat them as the "same").

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So, if we start with CN+, which has 4+5-1 (8) valence electrons, we note that the first two electrons contribute to bonding, while the next two cancel this out; the next four contribute to bonding, so the bond order is 4/2 = 2.

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Adding one more to give CN- would give the bond order 6/2 = 3. (If we added more electrons, each one would lower the bond order.)

Given a series of molecules with identical skeletal structures, the one with the highest bond order has the highest bond energy:

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learn more about bond orders at

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