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worty [1.4K]
3 years ago
12

117 milligrams (mg) of purified product was isolated from a chemical reaction. This experimental yield of product represents a 8

9.0% yield for the reaction. Calculate the theoretical yield, in milligrams (mg), for this reaction. Enter your answer as digits only, no units, using the proper number of significant figures.
Chemistry
1 answer:
Brut [27]3 years ago
5 0

Answer:

131 mg

Explanation:

Percent yield = 89%

Actual yield = 117 mg

Percent yield is given by

\text{Percent yield}=\dfrac{\text{Actual yield}}{\text{Theoretical yield}}\times 100\\\Rightarrow 89=\dfrac{117}{\text{Theoretical yield}}\times 100\\\Rightarrow \text{Theoretical yield}=\dfrac{117}{89}\times 100\\\Rightarrow \text{Theoretical yield}=131.46\approx 131\ \text{mg}

The theoretical yield, for this reaction is 131 mg.

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Answer : The balanced chemical reaction will be,

ZnS+2HBr\rightarrow ZnBr_2+H_2S

Explanation :

Balanced chemical reaction : It is defined as the reaction in which the number of atoms of individual elements present on reactant side must be equal to the product side.

If the amount of atoms of each type on the left and right sides of a reaction differs then to balance the equation by adding coefficient in the front of the elements or molecule or compound in the chemical equation.

The coefficient tell us about that how many molecules or atoms present in the chemical equation.

The given chemical reaction is,

ZnS+HBr\rightarrow ZnBr_2+H_2S

This reaction is an unbalanced chemical reaction because in this reaction number of hydrogen bromine atoms are not balanced.

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The balanced chemical reaction will be,

ZnS+2HBr\rightarrow ZnBr_2+H_2S

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