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fgiga [73]
2 years ago
13

Answer Please...I will give BRAINLIEST!!!

Mathematics
1 answer:
Black_prince [1.1K]2 years ago
7 0
Given that a fair die is rolled. We know there are six numbers in a fair die.
On rolling a die, the Sample space of the given event E = {1, 2, 3, 4, 5, 6}
Sample space of numbers less than 5 = {1, 2, 3, 4}
Clearly we can see that the number of favorable outcomes = 4
Hence, P(values less than 5) = 4/6 = 2/3.
To find the complement of rolling a number less than 5, we use the formula P' = 1 - P, where P' is the complement of P.
So, let P' be the complement probability of getting numbers less than 5
Now, P'(numbers less than 5) = 1 - P(numbers less than 5)
= 1 - 2/3
= 1/3.
Hence, the probability of the complement of rolling a number less than 5 by using a six-sided die is 1/3.
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3 years ago
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Step-by-step explanation:

We find the components of the forces in x-y-z

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Force of  Jill  in x     = F₂x= -82.3*cos45°= - 58.19 N (-x)

Force of  Jill  in y     =F₂y=-82.3*sin45°=   + 58.19 N (+y)

Force of  Jane  in x  =F₃x=125*cos45°=   + 88.4 N (+x)

Force of  Jane  in y   =F₃y=125*sin45°=   + 88.4  N (+y)

Calculating of the components of the net force the people exert on the donkey.

Fnx= F₂x+F₃x=( - 58.19+ 88.4 )N=30.2N (+x)

Fny= F₂y+F₃y=( 58.19+88.4 ) = 146.59 N (+y)

Fnz =F₁z=90.5 N  (+z)

Calculating of the magnitude of the net force the people exert on the donkey.

F_{n} =\sqrt{(F_{nx})^{2}+(F_{ny}) ^{2} +(F_{nz}) ^{2}   }

F_{n} =\sqrt{(30.2)^{2}+( 146.59) ^{2} +(90.5) ^{2}   }

F_{n} = 174.9 N

7 0
3 years ago
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