A square loop of wire lies in the plane of the page. A decreasing magnetic field is directed into the page. The induced current
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Molecular formulas:
- CH₂O;
- C₂H₄O₂;
- C₆H₁₂O₆.
The empirical formula of a compound tells only the ratio between atoms of each element. The empirical formula CH₂O indicates that in this compound,
- for each C atom, there are
- two H atoms, and
- one O atom.
The molecular weight (molar mass) of the molecule depends on how many such sets of atoms in each molecule. The empirical formula doesn't tell anything about that number.
It's possible to <em>add</em> more of those sets of atoms to a molecular formula to increase its molar mass. For every extra set of those atoms added, the molar mass increase by the mass of that set of atoms. The mass of one mole of C atoms, two mole of H atoms, and one mole of O atoms is .
- CH₂O- 30.0 g/mol;
- C₂H₄O₂- 30.0 + 30.0 = 2 × 30.0 = 60.0 g/mol;
- C₃H₆O₃- 30.0 + 30.0 + 30.0 = 3 × 30.0 = 90.0 g/mol.
It takes one set of those atoms to achieve a molar mass of 30.0 g/mol. Hence the molecular formula CH₂O.
It takes two sets of those atoms to achieve a molar mass of 60.0 g/mol. Hence the molecular formula C₂H₄O₂.
It takes sets of those atoms to achieve a molar mass of 180.0 g/mol. Hence the molecular formula C₆H₁₂O₆.
The wavelengths of the following quantum particles from the largest to the smallest is (d) > (a) = (e) > (b) > (c)
- De Broglie proposed that because light has both wave and particle properties, matter exhibits both wave and particle properties. This property has been explained as the dual behavior of matter.
- From his observations, de Broglie derived the relationship between the wavelength and momentum of matter. This relationship is known as de Broglie's relationship.
De Broglie's relationship is given by .
This can be written as .....(1) where λ is known as de Broglie wavelength and p is momentum , h = Plank’s constant .
As we know that mass of proton is greater than electron and photon .
(a)For photon , the momentum is given by ...(2) where c is the speed is the speed of light .
Putting E = 3eV in equation (2) , we get
Putting this value of p in equation (1) , we get
(b) As we know that kinetic energy is given by
...(3)
Where mass of electron is .
Putting K.E = 3eV in equation (3) , we get
Putting this value of p in equation (1) , we get
(c) Putting and K.E = 3eV in equation (3) , we get
Putting this value of p in equation (1) , we get
(d) Putting E = 0.3eV in equation (2) , we get
Putting this value of p in equation (1) , we get
(e) Putting in equation (1) , we get
On comparing the wavelength order should be (d) > (a) = (e) > (b) > (c) .
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