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Lina20 [59]
3 years ago
10

PLEASE ANSWER ASAP

Physics
1 answer:
kirill [66]3 years ago
4 0

Answer:

55.44.4 hjejjejjejej be

Explanation:

hehhehebebebbebeb

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Before it enters earths atmosphere, what type of force is acting on a spacecraft returning from the moon to earth?
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D. Gravitational force
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Supposing you were in space..in a weightless environment, would it require a force to set an object in motion? Explain..
Dvinal [7]

Answer:

Yes, a force is require to set an object in motion.

Explanation:

  • In space, even if you feel weightless, you are subject to motion. If you are orbiting the Earth, you are under the constant influence of Earth having a free-fall acceleration equal to the centripetal acceleration.
  • To disturb this orbital motion, an external force is required.
  • According to Newton's laws of motion, a force is required to change the state of the rest of a body or to change the velocity or direction if it is moving with uniform velocity along a straight line.
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3 years ago
87) Determine the equivalent resistances for the following circuits.
stepladder [879]

Answer:

15    and  11 ohms

Explanation:

First one =   For the parallel resistors 1 / (1/6 + 1/6 + 1/6) =   1/ (3/6 ) = 6/3 = 2 ohms   then add the 3 and the 10  = 15 ohms

second one    for the parallel portion   equiv =    (10+2)*24 / ( (10+2 + 24) = 8

  then add the  3 in series = 11 ohms

8 0
2 years ago
Can someone help?
laila [671]

Answer:

i) 21 cm

ii) At infinity behind the lens.

iii) A virtual, upright, enlarged image behind the object

Explanation:

First identify,

object distance (u) = 42 cm (distance between  object and lens, 50 cm - 8 cm)

image distance (v) = 42 cm (distance between  image and lens, 92 cm - 50 cm)

The lens formula,

\frac{1}{v} -\frac{1}{u} =\frac{1}{f}

Then applying the new Cartesian sign convention to it,

\frac{1}{v} +\frac{1}{u} =\frac{1}{f}

Where f is (-), u is (+) and  v is (-) in  all 3  cases. (If not values with signs have to considered, this method that need will not arise)

Substituting values you get,

i) \frac{1}{42} +\frac{1}{42} =\frac{1}{f}\\\frac{2}{42} =\frac{1}{f}

f = 21 cm

ii) u =21 cm, f = 21 cm v = ?

Substituting in same equation\frac{1}{v} =\frac{1}{21} =\frac{1}{21} \\\\\frac{1}{v} = 0\\

  v ⇒ ∞ and image will form behind the lens

iii) Now the object will be within the focal length of the lens. So like in the attachment, a virtual, upright, enlarged image behind the object.

7 0
3 years ago
Find the mass of glass which has the same volume as 5.4 g of aluminium, if density of aluminum is 2700 kg/m3 and that of glass i
White raven [17]

Answer:

Mass of glass, m=5g

Explanation:

Soluton is in the attached jpg

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3 years ago
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