The prime factorization of 88 is 11 x 2 x 2 x 2 the only factor of 88 that prime numbers are 2 and 11
3k+10=2k-21
move 2k to the other side
sign changes from +2k to -2k
3k-2k+10=2k-2k-21( combine like terms)
3k-2k+10= -21
k+10=-21
move +10 to the other side
k+10-10= -21-10
k= -21-10
answer:
k= -31
Answer:
Step-by-step explanation:
Instead, since the divisor is in the form of 
, use what is called Synthetic Division. Remember, in this formula, 
gives you the OPPOSITE terms of what they really are, so do not forget it. Anyway, here is how it is done:
4| 1 −5 7 −12
↓ 4 −4 12
_______________
1 −1 3 0 →
You start by placing the 
in the top left corner, then list all the coefficients of your dividend [x³ - 5x² + 7x - 12]. You bring down the original term closest to then begin your multiplication. Now depending on what symbol your result is tells you whether the next step is to subtract or add, then you continue this process starting with multiplication all the way up until you reach the end. Now, when the last term is 0, that means you have no remainder. Finally, your quotient is one degree less than your dividend, so that 1 in your quotient can be an 
, the −1 [
] follows right behind it, and bringing up the rear, comes the 3, giving you the quotient of .
I am joyous to assist you anytime.
Answer: 20 oranges and 5 mangoes
Step-by-step explanation:
Define the following:
x = number of oranges
y = number of mangoes
Make the following system of equations:
x + y = 25
0.35x + 1.00y = 12.00
Solve for x:
y = 25 - x
⇒ 0.35x + 1.00(25 - x) = 12.00
⇒ 0.35x + 25 - x = 12.00
⇒ -0.65x = -13.00
⇒ x = 20
Solve for y:
20 + y = 25
y = 5
∴ 20 oranges and 5 mangoes were purchased.
Answer:
19
Step-by-step explanation:
maximum no. of bag filled by 4275 sweets,is
4275/28 ~=152
therefore , there is 4256 sweets in 152 bags
therefore,4275-4256=19 sweets are left
