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Trava [24]
2 years ago
6

Htuhrjnkemldjrhftrfejdkws

Mathematics
1 answer:
kondaur [170]2 years ago
3 0

Answer:

2z + 4 = 8

Z = 2

Step-by-step explanation:

2z + 4 = 8

-4. -4

2z = 8

—- —

2. 2

z. =. 4

Easy Peasy! Hope this helped :) have great day!!

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In science class, Paul estimates the volume of a sample to be 37 mL. The actual volume of the sample is 39 mL. Find the percent
svet-max [94.6K]

Answer:

the answer is 5.1%

Step-by-step explanation:

first you divide 37 by 39 to get .94871795

next you would subtract 1 by that number and you get

.05128205 which can be rounded to .051 or 5.1%

7 0
3 years ago
Simplify: <br><br> 3c-5d+5d<br><br> Pls
Arturiano [62]

Answer:

3 c

Step-by-step explanation:

Simplify the following:

5 d - 5 d + 3 c

Hint: | Combine like terms in 5 d - 5 d + 3 c.

5 d - 5 d = 0:

Answer: 3 c

5 0
4 years ago
Read 2 more answers
Select the possible dimensions of a rectangular prism with volume of 48 in.
xenn [34]

Answer:

6 in * 4 in * 2 in

Step-by-step explanation:

Given the following data;

Volume of rectangular prism = 48 in³

To find its possible dimensions;

Volume of rectangular prism = length * breadth * height

48 = length * breadth * height

From the given options, option B is most likely to be its dimensions.

Where;

Length = 6 in

Breadth = 4 in

Height = 2 in

Substituting into the formula, we have;

48 in = 6 * 4 * 2

48 in = 48 in

8 0
3 years ago
A projectile is fired with muzzle speed 250 m/s and an angle of elevation 45° from a position 30 m above ground level. Where doe
qaws [65]

The projectile's horizontal and vertical positions at time t are given by

x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ\,t

y=30\,\mathrm m+\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ\,t-\dfrac g2t^2

where g=9.8\dfrac{\rm m}{\mathrm s^2}. Solve y=0 for the time t it takes for the projectile to reach the ground:

30+\dfrac{250}{\sqrt2}t-4.9t^2=0\implies t\approx36.2458\,\mathrm s

In this time, the projectile will have traveled horizontally a distance of

x=\dfrac{250\frac{\rm m}{\rm s}}{\sqrt2}(36.2458\,\mathrm s)\approx6400\,\mathrm m

The projectile's horizontal and vertical velocities are given by

v_x=\left(250\dfrac{\rm m}{\rm s}\right)\cos45^\circ

v_y=\left(250\dfrac{\rm m}{\rm s}\right)\sin45^\circ-gt

At the time the projectile hits the ground, its velocity vector has horizontal component approx. 176.77 m/s and vertical component approx. -178.43 m/s, which corresponds to a speed of about \sqrt{176.77^2+(-178.43)^2}\dfrac{\rm m}{\rm s}\approx250\dfrac{\rm m}{\rm s}.

7 0
3 years ago
a triangle has a side length of 3/4 inch and a side length of 3in what could be the length in inches of the third side of the tr
eimsori [14]
I think the answer will be 6.75
6 0
3 years ago
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