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alexgriva [62]
1 year ago
15

A standard six-sided die is rolled onto a table. The product of the visible numbers is 144. What is the number on the bottom sid

e of the die?
Mathematics
1 answer:
denis-greek [22]1 year ago
8 0
<h3>Answer:  5</h3>

Explanation:

This is something you could do by trial and error.

The visible numbers are 1,2,3,4,6 which multiply to 144.

Another approach is to notice that 5 is not a factor of 144, so it must be the hidden value not part of the items multiplied.

Every other number 1,2,3,4,6 is a factor of 144.

1*144 = 144

2*72 = 144

3*48 = 144

4*36 = 144

6*24 = 144

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An office room is 12 ft by 10 ft with a door that is 30 inches wide. How many feet of baseboard are needed to go around the room
Lina20 [59]
Draw a diagram to illustrate the problem as shown below.
The length of baseboard needed is AB + BC + CD + DE + FE.
Note that 30 in = 30/12 ft = 2.5 ft.

Because of the door opening,
AB + EF = 12 - 2.5 = 9.5 ft
Also,
BC = DE = 10 ft
CD = 12 ft.

The amount of baseboard needed is
AB + BC + CD + DE + FE
= (AB + EF) + BC + CD + DE
= 9.5 + 10 + 12 + 10
= 41.5 ft

Answer:
41.5 feet of baseboard.

7 0
3 years ago
Instructions: Find the measure of the indicated angle to the<br> nearest degree
Artemon [7]

Answer:

? = 57

Step-by-step explanation:

Since this is a right triangle, we can use trig functions

cos ? = adj/ hyp

cos ? = 14/26

Taking the inverse cos of each side

cos ^-1 ( cos ?) = cos ^-1 ( 14/26)

? = 57.42102961

To the nearest degree

? = 57

5 0
2 years ago
I need help answer this question..
Kaylis [27]
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8 0
3 years ago
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mina [271]
Top left is the right answer hope this helps <3
7 0
2 years ago
April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t
dusya [7]

Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

h(max) = 27 ft

the maximum height of the​ arrow is 27 ft.

8 0
2 years ago
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