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2 years ago

Use the Pythagorean Theorem to find the length of the hypotenuse in the triangle shown below.

Mathematics

1 answer:

forsale [732]2 years ago

6 0

Answer:

Step-by-step explanation:

The square length of hypotenuse is equal to the sum of square length of two legs:

12^2 + 35^2 = c^2

144 + 1225 = c^2

1369 = c^2 find the root for both sides

37 = c

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What is the answer to the equation 13=1/6y + 2x

Eddi Din [679]

13=1/6y+2x
-1/6y -1/6y
-1/6y+13=2x
-13 -13
-1/6y=2x-13
*-6 *-6
y=-12x-13

*I multiply it by -6 because -6 is the reciprocal of -1/6, and I can't divide -1/6, actually I can, but it just going to be more confusing that way, and the fastest way to get rid of the -1/6 when you solving this type of equation is multiply it by its reciprocal.

6 0

3 years ago

I can't find the answer

Rudik [331]

Answer: what grade is this

Step-by-step explanation:

3 0

2 years ago

Use the recursive formula to answer the question. What’s the 7th term in the sequence?

tensa zangetsu [6.8K]

Answer:

a7 = 36

Step-by-step explanation:

Here, we are to use the recursive formula to calculate the 7th term( we add the preceding term to 4 so as to get the succeeding term)

a1 = 12

using the recursive formula given in the question

a2 = 12 + 4 = 16

a3 = 16 + 4 = 20

a4 = 20 + 4 = 24

a5 = 24 + 4 = 28

a6 = 28 + 4 = 32

a7 = 32 + 4 = 36

3 0

3 years ago

On Texas Avenue between University Drive and George Bush Drive, accidents occur according to a Poisson process at a rate of thre

Zarrin [17]

Answer:

(a) The probability is 0.6514

(b) The probability is 0.7769

Step-by-step explanation:

If the number of accidents occur according to a poisson process, the probability that x accidents occurs on a given day is:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is the mean number of accidents per day and t is the number of days.

So, for part (a), a is equal to 3/7 and t is equal to 1 day, because there is a rate of 3 accidents every 7 days.

Then, the probability that a given day has no accidents is calculated as:

$P(x)=\frac{e^{-3/7}*(3/7)^{x}}{x!}$

$P(0)=\frac{e^{-3/7}*(3/7)^{0}}{0!}=0.6514$

On the other hand the probability that February has at least one accident with a personal injury is calculated as:

P(x≥1)=1 - P(0)

Where P(0) is calculated as:

$P(x)=\frac{e^{-at}*(at)^{x} }{x!}$

Where a is equivalent to (3/7)(1/8) because that is the mean number of accidents with personal injury per day, and t is equal to 28 because 4 weeks has 28 days, so:

$P(x)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{x}}{x!}$

$P(0)=\frac{e^{-(3/7)(1/8)(28)}*((3/7)(1/8)(28))^{0}}{0!}=0.2231$

Finally, P(x≥1) is:

P(x≥1) = 1 - 0.2231 = 0.7769

3 0

3 years ago

$10,000 is compounded semiannually at 12% interest for t years. what expression represents the amount of money after t years?

kari74 [83]

To solve this, you can do the is over of equals to % over hundred.
is %
__ = ____
of 100
10,000 12
_____ = ____
t 100
1,000,000=12t
__
t=83,333.33
i hope this helps!

3 0

3 years ago