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balandron [24]
2 years ago
10

If h and j are positive, (h+j)2 = 73 and h2 +j2 = 51, what is hj?

Mathematics
1 answer:
kkurt [141]2 years ago
3 0

Answer:

hj = 11

Step-by-step explanation:

  • (h+j)^2=73,\:\: and\:\: h^2+j^2 =51 (Given)

  • (h+j)^2 = h^2+j^2 +2hj

  • \implies 73= 51 +2hj

  • \implies 73- 51 =2hj

  • \implies 22 =2hj

  • \implies hj = \frac{22}{2}

  • \implies hj = 11
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Step-by-step explanation:

The distributive property says a factor outside parentheses multiplies each term inside parentheses. It is an error to do addition of the factor, or to miss multiplying a term.

In Step 2 of this "solution", the factor of 3 is erroneously <em>added</em> to each coefficent inside parentheses. It should be <em>multiplied</em>.

Correct Step 2: 9x -12 = 13 +2x

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The rest of the solution should be ...

  Step 3: 9x -2x = 13 +12

  Step 4: 7x = 25

  Step 5: x = 25/7

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<em>Check</em>

  3(3(25/7) -4) = 8 + 2(25/7) +5

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(B) 2/3 [√(4-x)]^3

Step-by-step explanation:

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(A) Any function in square root is equal to or same as the function raised to the power of 1/2

To integrate, add 1 to the power of the function. That's 1/2 + 1 = 3/2

Divide the function by this new power 3/2. This implies multiplying the function by the inverse of 3/2. The inverse of 3/2 is 2/3.

Also, when a function is raised to the power of a fraction instead of a whole number, you take the 'denominator' root of the function, and then raise the function to the power of the numerator.

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