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denis-greek [22]
3 years ago
8

Simplify sqrt(45/7y)

Mathematics
1 answer:
Alex_Xolod [135]3 years ago
7 0
8.2y that the cayse 45 is 7 byt 8.2
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Find the area of a trapezium whose parallel sides are 28.7 cm and 22.3 cm and distance between parallel sides is 16 cm.
puteri [66]

Given:

The parallel sides of a trapezium are 28.7 cm and 22.3 cm.

The distance between parallel sides is 16 cm.

To find:

The area of a trapezium.

Solution:

The area of the trapezium is:

A=\dfrac{a+b}{2}h

Where, a,b are parallel sides and h is the vertical distance between the parallel sides.

Putting a=28.7, b=22.3,h=16 in the above formula, we get

A=\dfrac{28.7+22.3}{2}\times(16)

A=\dfrac{51}{2}\times 16

A=51\times 8

A=408

Therefore, the area of the trapezium is 408 square cm.

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Answer:

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3330/100=33.3

100-32=68

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