Simplify sqrt(45/7y)

Mathematics

1 answer:

Alex_Xolod [135]2 years ago

7 0

8.2y that the cayse 45 is 7 byt 8.2

You might be interested in

The data in the table compares x, the number of pages in a chapter, to y, the amount of time, in minutes, spent reading. The fun

Mamont248 [21]

Answer:The answer is A, 15 I believe if i did the math right.

Step-by-step explanation: First you take the equation: f(x)= 0.86x-0.09

Then you plug in x witch in this case is 18 so f(18)=0.86(18)-0.09= 15.39 So round to the nearest whole number and you get 15.

5 0

3 years ago

Read 2 more answers

Two horses are ready to return to their barn after a long workout session at the track. the horses are at coordinates H(1,10) an

ss7ja [257]

The given information are the coordinates of points H, Z and B. So, the first step to do is to plot these points on a Cartesian plane as shown in the attached picture. We can deduce visually that horse Z is closer to the barns than horse H. But, to further justify the answer, we have to provide the magnitude of the distance of horses H and Z to barn B. In this approach, we use the distance formula:

d = √(x₂ - x₁)² + (y₂ - y₁)²

Use the coordinates of the two points to know their linear distances. These are represented by the red and green lines for each of the horses.

Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = √(⁻3 - 1)² + (⁻9-10)²
Distance between H and B = 19.4165

Since the scale is 1 unit = 100 meters, the actual distance between horse H and barn B is 19.416*100 = 1,941.65 meters

Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = √(⁻3 - 10)² + (⁻9-1)²
Distance between Z and B = 16.4012

Since the scale is 1 unit = 100 meters, the actual distance between horse Z and barn B is 16.4012*100 = 1,640.12 meters

Comparing the distances: 1,941.65 meters > 1,640.12 meters. Therefore, it justifies that horse Z is nearer to the barn.