Question

A chemical reaction done at STP conditions is supposed to produce 0.011 moles of CO2 gas. How many liters of gas will that be?

Answer 1

Answer:

V = 0.24 L.

Explanation:

Hello there!

In this case, it is possible to approach this problem by using the ideal gas equation defined by:

$PV=nRT$

Whereas our unknown is V, volume, and we solve for it as follows:

$V=\frac{nRT}{P}$

Then since the STP conditions are ate 273.15 K and 1 atm, the volume of 0.011 moles of CO2 gas turns out to be:

$V=\frac{0.011mol*0.08206\frac{atm*L}{mol*K}*273.15K}{1atm}\\\\V=0.24L$

Regards!