As, using formula.........0.054/(.667/18)
=.o54/.037
=1.45 approx
so the answer
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Answer:
9% solution by mass
Explanation:
If there is 500 gm of solution and 45 g of it is glucose then:
45/500 * 100% = 9 % solution
Answer:
There are 4 tryptophans in the protein.
Explanation:
According to question, protein contains one tyrosine residue and say x number of tryptophans.
Concentration of protein solution = 1.0 micromolar = 
Molar absorptivity of a protein solution : 


Length of the cuvette = l = 1.0 cm
Absorbance of protein solution at 280 nm = A = 0.024
( Beer-Lambert's law)

Solving for x :
x = 4
There are 4 tryptophans in the protein.