<u>Answer:</u> A. constant
Without any air resistance, as the golf ball falls into the well, its speed is constant.
<u>Explanation:</u>
Given that when the ball is released,<em>there is no air resistance acting on ball. So the ball is freely falling.
</em>
The only force acting on the freely falling body is the gravitational force pulling the body towards the centre of the earth.Here the only acceleration acting on the body is the <em>acceleration due to gravity.</em>
The acceleration due to gravity is 
. so through out the journey of the ball,the acceleration is . <em>So as the acceleration is constant, the speed is also constant.</em>
Answer:
The answer to your question is below
Explanation:
a) CI Chlorine is located in group VIIA, so its must gain one electron to be stable.
b) Se Selenium is located in group VIA, it must gain 2 electrons to be stable.
c) N Nitrogen is located in group VA, it must gain 3 electrons to be stable.
d) I Iodine is located in group VIIA, so it must gain 1 electron to be stable.
e) S sulfur is located in group VIA, so it must gain 2 electrons to be stable.
Answer:
The atom is oxidized is Ca.
Explanation:
- The oxidation-reduction reaction contains a reductant and an oxidant (oxidizing agent).
- The oxidation process is the process in which electrons are lost and produce positively charged ions.
- The reduction process is the process in which electrons is gained and negatively charge ions are produced.
- In the reaction of chlorine with calcium:
<em>Ca + Cl₂ → CaCl₂,</em>
Ca loses 2 electrons and is oxidized to Ca²⁺. (Ca <em>→</em> Ca²⁺ + 2e).
Cl is gains 2 electrons in "Cl₂, oxidation state zero" and is reduced to Cl⁻. (Cl₂ + 2e <em>→</em> 2Cl⁻).
Answer:
119 kCal per serving.
Explanation:
The heat energy necessary to elevates water's temperature from 23.4°C to 37.9°C can be calculated by the equation below:
Q = mcΔT
Q: heat energy
m: mass in g
c: specific heat capacity in cal/g°C
ΔT = temperature variation in °C
m is the mass of water, considering the density of water to be 1g/mL, 100 mL of water weights 100g. Therefore:
Q = 100 g x 1.00 cal/g°C x (37.9 - 23.4)°C
Q = 1450 cal
1450 cal ____ 0.341 g peanuts
x ____ 28 g peanuts
x = 119061.58 cal
This means that the cal from fat per serving of peanuts is at least 119 kCal.
