Answer:
14
Step-by-step explanation:
Hope it helps
Therefore, the answer is <u>1</u><u>0</u><u>2</u><u>4</u><u>.</u>
<h3>
<em>Benjemin</em></h3>
Answer: See below
Step-by-step explanation:
27. -(a-3)
28. (b-1)(b+3)
29. (c+4)(c+5)
30. d(d+5)
31. -(3/4)(2e-5)
Sorry - I don't have time to enter the details. Look for areas where the expressions can be factored in a manner that forms as many equivalent expressions in both the numerator and denominator.
For example: In problem 30:
(5d-20)/(d^2+d-20) * [??]/20d = 1/4
Factor:
<u>(5(d-4))</u> <u>d(d+5)</u> = 1/4
(d-4)(d+5<u>)</u> 20d
The (d-4), d+5, and d terms cancel, leaving
5/20 = 1/4
Which set of ordered pairs represents a function? {(2, –2), (1, 5), (–2, 2), (1, –3), (8, –1)} {(3, –1), (7, 1), (–6, –1), (9, 1
ra1l [238]
A function can't have x repeating any of the same number twice for example the first one (2, -2), (1, 5), (-2, 2), (1,-3), (8,-1) you have two 1's (1,5) and (1,-3) the x is the first number. Now a function can have the same y value. So your answer is (3, -1), (7,1), (-6,-1), (9,1), and (2,-1) you have to have all different x values in order for it to be a function. Hope that helps.
Answer:
yes?
Step-by-step explanation:
??? can u say exactly what the question is please? thank you
