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sleet_krkn [62]
2 years ago
7

Michaela’s favorite fruit to snack on is the “cotton candy grape.” She has $20 to spend on a gallon of cider that costs $3.50 an

d can spend the rest of her money on cotton candy grapes. The grapes cost $3.75 per pound. How many pounds of grapes can Michaela buy without spending more than the rest of the money after buying the cider?
Mathematics
1 answer:
daser333 [38]2 years ago
8 0

Answer:

So, to answer this problem, we first have to get rid of the cider cost.

$20-$3.50=$16.50

Since we have $16.50 left, now we have to see how much cotton candy grapes Michaela can buy.

1 pound- $3.75

2 pound- $7.50

3 pound- $11.25

4 pound- $15

5 pound- $18.75

When Michaela buys 5 pounds of grapes, she gets a cost of $18.75.

Since $18.75 is $2.25 more than $16.50, the only option she can choose is 4 pounds.

When Michaela buys 4 pounds, she will spend $15 and she will still have $1.50 left. (If there is no tax.)

In summary, Micheala can buy 4 pounds of grapes without spending more than the rest of the money after buying cider.

(By the way, I LOVE cotton candy grapes.)

Hope this helps!

:)

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3 years ago
Read 2 more answers
<img src="https://tex.z-dn.net/?f=12x%20%5E%7B2%7D%20%20%2B%204x%20%2B%2020" id="TexFormula1" title="12x ^{2} + 4x + 20" alt="1
Nesterboy [21]
<h3>Answer: </h3>

The GCF is 4

The polynomial factors to 4(3x^2+x+5)

==========================================================

Further explanation:

Ignore the x terms

We're looking for the GCF of 12, 4 and 20

Factor each to their prime factorization. It might help to do a factor tree, but this is optional.

  • 12 = 2*2*3
  • 4 = 2*2
  • 20 = 2*2*5

Each factorization involves "2*2", which means 2*2 = 4 is the GCF here.

We can then factor like so

12x^2 + 4x + 20\\\\4*3x^2 + 4*x + 4*5\\\\4(3x^2 + x + 5)

The distributive property pulls out that common 4. We can verify this by distributing the 4 back in, so we get the original expression back again.

The polynomial inside the parenthesis cannot be factored further. Proof of this can be found by looking at the roots and noticing that they aren't rational numbers (use the quadratic formula).

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2 years ago
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