Let after n week both tanks have same quantity of water .
for first tank
=============
tank hold 540 gallon of water ,
leaking of water 4 gallon /week
so, in n week water leak from the tank =4× n = 4n
now, after n week quantity of water in the tank = 540 -4n
for second tank
==============
quantity of water in the tank =720 gallon
leaking of water at the rate = 7gallon/week
so, after n week water leak from the tank = 7× n =7n
after n week quantity of water rest in the tank = 720 -7n
now ,
according to question ,
water in first tank = water in second tank
540 -4n = 720 -7n
7n -4n = 720 -540
3n = 180
n = 60
hence , after 60 week both tank have same quantity of water.
Answer:
14.52
Step-by-step explanation:
13.57 + 13.57 x 7% = 13.57 x (1+7/100) =13.57 x 107/100 = 14.52
Answer: -$266
Explanation: -32x8 because of 8 tickets, add 10 to the total debt because of the fee.
Answer:
D. (4,3)
Step-by-step explanation:
(-3,4)
Reflection in the y-axis:
Same y, -ve x
(3,4)
Reflection in y = x
(x,y) goes to (y,x)
(3,4) goes to (4,3)
The answer is 16
Refer image for working :-
Drop comments if any doubt arises.