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r-ruslan [8.4K]
2 years ago
12

Please solve the Problem.

Physics
1 answer:
Pie2 years ago
3 0

The electric flux is - 4.80 × 10∧5 N m2 C-1

How to calculate the electric flux

Use the formula:

Electric flux, ΦE = EScosθ

Where,

E = electric flux

S = area of the rectangular surface = length × breadth = 6.00 × 3.00 = 18.00 m²

E = magnitude = 2. 70 × 10∧4 N/C

θ = the angle between the electric field lines = 15. 7°

Substitute the values into the equation

EФ =  2. 70 × 10∧4 × 18. 00 × Cos (15.7)

EФ = 2. 70 × 10∧4 × 18. 00 × -0.9999

EФ= - 4.79 × 10∧5 N m2 C-1

Therefore, the electric flux is - 4.80 × 10∧5 N m2 C-1

Learn more about electric flux here:

brainly.com/question/14529872

#SPJ1

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An ant crawls along a sidewalk with a velocity of 0.1 m/s in a direction that is 45° relative to edge of the sidewalk. If it has
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3 years ago
A giant wall clock with diameter d rests vertically on the floor. The minute hand sticks out from the face of the clock, and its
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Answer:

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The x-component of the length of the minute hand is:

d_{x}(t)=dcos(\theta (t)) (1)

  • d is the length of the minute hand (d=D/2)
  • D is the diameter of the clock
  • t is the time (min)

Now, using the angular kinematic equations we can express the angle in term of angular velocity and time. As we know, the minute hand moves with a constant angular velocity, so we can use this equation:

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Also we know, that the minute hand moves 90 degrees or π/2 rad in 15 min, so using the definition of angular velocity, we have:

\omega=\frac{\Delta \theta}{\Delta t}=\frac{\theta_{f}-\theta_{i}}{t_{f}-t{i}}=\frac{\pi/2-0}{15-0}=\frac{\pi}{30}

Now, let's put this value on (2)

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Finally the length x(t) of the shadow of the minute hand as a function of time t, will be:

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I hope it helps you!

6 0
3 years ago
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a_sh-v [17]

Answer: 4850N

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Recall that Force is the product of the mass of an object and the acceleration by which it moves

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