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Flauer [41]
3 years ago
11

A radioactive particle has a half life of 1 second. If it moves at 3/5 the speed of light, from my point of view standing still

it's new half-life will be
Physics
1 answer:
AVprozaik [17]3 years ago
7 0

The half-life observed by an observer at rest is 1.25 s

Explanation:

In this problem, the particle is travelling at a significant fraction of the speed of light: therefore, we have to consider the phenomenon of the time dilation. The half-life of the particle as measured by an observer at rest is given by

T=\frac{T_0}{\sqrt{1-(\frac{v}{c})^2}}

where

T_0 is the proper half-life of the particle

v is the speed of the particle

c is the speed of light

For the particle in this problem,

T_0 = 1 s

v=\frac{3}{5}c=0.6 c

Substituting into the equation, we find:

T=\frac{1}{\sqrt{1-(\frac{0.6c}{c})^2}}=1.25 s

#LearnwithBrainly

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A capacitor has a capacitance of 0. 40 µF at a voltage of 9. 0 V. What is the charge on each plate of the capacitor? µC.
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The capacitor is a device that can store electrical energy. It is a two-conductor configuration. The charge on each plate of the capacitor will be 3.6 µC.

<h3>What is a capacitor?</h3>

A capacitor is a device that can store electrical energy. It is a two-conductor configuration separated by an insulating medium that carries charges of equal size and opposite sign.

An electric insulator or vacuum, such as glass, paper, air, or a semi-conductor termed a dielectric, can be used as the non-conductive zone.

The given data in the problem is;

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The formula for the capacitor is given as;

\rm Q=CV \\\\ \rm Q=0. 40 \times 9. 0 \\\\ \rm Q=3.6 \ \mu C.

Hence the charge on each plate of the capacitor will be 3.6 µC.

To learn more about the capacitor refer to the link;

brainly.com/question/14048432

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