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Flauer [41]
3 years ago
11

A radioactive particle has a half life of 1 second. If it moves at 3/5 the speed of light, from my point of view standing still

it's new half-life will be
Physics
1 answer:
AVprozaik [17]3 years ago
7 0

The half-life observed by an observer at rest is 1.25 s

Explanation:

In this problem, the particle is travelling at a significant fraction of the speed of light: therefore, we have to consider the phenomenon of the time dilation. The half-life of the particle as measured by an observer at rest is given by

T=\frac{T_0}{\sqrt{1-(\frac{v}{c})^2}}

where

T_0 is the proper half-life of the particle

v is the speed of the particle

c is the speed of light

For the particle in this problem,

T_0 = 1 s

v=\frac{3}{5}c=0.6 c

Substituting into the equation, we find:

T=\frac{1}{\sqrt{1-(\frac{0.6c}{c})^2}}=1.25 s

#LearnwithBrainly

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A drone flies 8 m/s due East with respects to the wind. The wind is blowing 6 m/s due North with respects to the ground. What is
vekshin1

Answer:

B. 10m/s

Explanation:

If a drone flies 8 m/s due East with respects to the wind and the wind is blowing 6 m/s due North, the speed of the drone with respect to the ground is its displacement.

Displacement is calculated using Pythagoras theorem.

d² = 8²+6²

d² = 64+36

d² = 100

Square root both sides

√d² = √100

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Option B is correct

8 0
3 years ago
The force between a pair of .005 charges is 750 N. What is the distance between them?
Ganezh [65]

Question: The force between a pair of 0.005 C is 750 N. What is the distance between them?

Answer:

17.32 m

Explanation:

From coulomb's Law,

F = kqq'/r²........................... Equation 1

Where F = Force between the force, q' and q = both charges respectively, k = coulomb's constant, r = distance between both charges.

make r the subject of the equation above

r = √(kqq'/F)..................... Equation 2

From the question,

Given: q = q' = 0.005 C, F = 750 N

Constant: k = 9.0×10⁹ Nm²/C².

Substitute these values into equation 2

r = √(9.0×10⁹×0.005×0.005/750)

r = √(300)

r = 17.32 m.

Hence the distance between the pair of charges = 17.32 m

6 0
3 years ago
Is it polar or non-polar... i need help on all of them plz hurry
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Answers

1.) non-polar

2.) non-polar

3.) Polar

4.) Polar

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The answer for this change in the magnitude of momentum is the same for both because momentum is always conserved so both vehicles have the identical change. 
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What does the speed of sound depend on ?
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Answer:

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