Answer:
Option (D)
Explanation:
Reflection is the phenomenon in which a ray of light strikes on a smooth and polished surface and then bounce back into the same medium at same angle.
There are two types of reflection.
1. Regular reflection or specular reflection
2. Irregular reflection or diffused reflection
When a parallel beam of light falls on a smooth and highly polished surface and after reflection the rays are also parallel to each other, it is called regular reflection.
When after parallel beam of light falls on a rough surface and after reflection the rays of light goes in random directions, it is called diffused reflection.
The rays reflected at 90 degree to - 90 degree in diffused refectory.
Answer:
Explanation:
capacitance of parallel plate capacitor
c = ε A / d , d is distance between plates , A is surface area , ε is constant
As d becomes two times , Capacitance c = 1/ 2 times ie c / 2
potential V = Q / C
Q is constant , potential
v = Q / c /2
= 2 . Q / C
= 2 V
So potential difference becomes 2 times.
NEW P D = 398 X 2
= 796 V.
Answer:
Explanation:
There are 4 forces. These are 1) Gravity, 2) Weak Nuclear Force, 3) Electromagnetism, and 4) Strong Nuclear Force.
Order of strength from weakest to strongest: Gravity, Weak Nuclear Force, Electromagnetism, Strong Nuclear Force
Type of Range:
Gravity - Unlimited range
Weak Nuclear Force - Limited range
Electromagnetism - Infinite range
Strong Nuclear Force - Limited Range
Found in:
Gravity - Exists between all objects with mass
Weak Nuclear Force - Governs over beta decays like the emission of electron or positron
Electromagnetism - the attraction found between particles that are electrically charged
Strong Nuclear Force - Found in atoms and subatomic particles. It is responsible for holding the atoms' nucleus together.
Answer:
0.167m/s
Explanation:
According to law of conservation of momentum which States that the sum of momentum of bodies before collision is equal to the sum of the bodies after collision. The bodies move with a common velocity after collision.
Given momentum = Maas × velocity.
Momentum of glider A = 1kg×1m/s
Momentum of glider = 1kgm/s
Momentum of glider B = 5kg × 0m/s
The initial velocity of glider B is zero since it is at rest.
Momentum of glider B = 0kgm/s
Momentum of the bodies after collision = (mA+mB)v where;
mA and mB are the masses of the gliders
v is their common velocity after collision.
Momentum = (1+5)v
Momentum after collision = 6v
According to the law of conservation of momentum;
1kgm/s + 0kgm/s = 6v
1 =6v
V =1/6m/s
Their speed after collision will be 0.167m/s
