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Leona [35]
2 years ago
12

3.accuracy is gauged by comparing the measured value of a known standard to its true value. assuming the mass of the water repre

sents a standard for the true volume of water, which piece of glassware has the highest degree of accuracy
Physics
1 answer:
tangare [24]2 years ago
4 0

The glassware with the highest degree of accuracy is 250 mL beaker.

<h3>What is accuracy?</h3>

When in an experiment, a value is measured 5 times, then if the values measured are same for most of the time or like three times out of five, it said to be accurate. The phenomenon is accuracy.

Accuracy compares the experimental value to the theoretical value.

Accepted density of water = 0.99 g/mL

1. 10 mL cylinder

Mass of water = 6.76 g

Volume of water = 6.8 mL

Density = mass /Volume

density = 6.76/6.8 = 0.99412 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99412 - 0.99 / 0.99 ] x 100

% error = 0.416 %

2. 50 mL cylinder

Mass of water = 24 g

Volume of water = 24.2 mL

density = 24/24.2 = 0.9917 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9917 - 0.99 / 0.99 ] x 100

% error = 0.172 %

3. 25 mL cylinder

Mass of water = 17 g

Volume of water = 17.1 mL

density = 17/17.1 = 0.99415 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.99415 - 0.99 / 0.99 ] x 100

% error = 0.419 %

4. 250 mL beaker

Mass of water = 35 g

Volume of water = 35.3 mL

density = 35/35.3 = 0.9915 g/mL

Percentage error = [Observed value - Accepted value/ Accepted value ] x 100

% error = [0.9915 - 0.99 / 0.99 ] x 100

% error = 0.152 %

Lesser the percentage error, higher is the accuracy.

Thus, 250 mL beaker has the highest degree of accuracy.

Learn more about accuracy.

brainly.com/question/13099041

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Answer:

Zero

Explanation:

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B_1=\dfrac{\mu_oI_1}{2\pi r}

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F_2=\dfrac{\mu_oI_1I_2 l}{2\pi r}

Similarly, force acting in wire 1 is given by :

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F_2=-F_1

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3 years ago
Finish A 16 N force is applied to an object and 96 J of work is done. How far was the object moved?
Lina20 [59]

Answer:

\boxed {\boxed {\sf 6 \ meters}}

Explanation:

Work is the product of force and distance.

W=F*d

We know that 96 Joules of work were done and a 16 Newton force was applied to the object.

  • W= 96 J
  • F= 16 N

Substitute the values into the formula.

96 \  J= 16 \ N * d

First, let's convert the units. This will make cancelling units easier later in the problem. 1 Joule (J) is equal to 1 Newton meter (N*m), so the work of 96 Joules equals 96 Newton meters.

96 \ N*m= 16 \ N * d

Now, solve for distance by isolating the variable, d. It is being multiplied by 16 Newtons and the inverse of multiplication is division. Divide both sides of the equation by 16 N.

\frac {96 \ N*m}{16 \ N}= \frac{16 \ N *d}{16 \ N}

\frac {96 \ N*m}{16 \ N}=d

The units of Newtons cancel.

\frac {96}{16} \ m = d

6 \ m = d

The object moved a distance of <u>6 meters.</u>

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C. West to east is the correct answer
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Answer: the answer is most likely that the mirror is 120 cm tall as well

Explanation:mark brainliest PLEASE.

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3 years ago
What can you say about the magnitudes of the forces that the balloons exert on each other?
maxonik [38]

Answer:

F_G=G. \frac{m_1.m_2}{R^2} gravitational force

F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2} electrostatic force

Explanation:

The forces that balloons may exert on each other can be gravitational pull due to the mass of the balloon membrane and the mass of the gas contained in each. This force is inversely proportional to the square of the radial distance between their center of masses.

The Mutual force of gravitational pull that they exert on each other can be given as:

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m_1\ \&\ m_2 are the masses of individual balloons

R= the radial distance between the  center of masses of the balloons.

But when  there are charges on the balloons, the electrostatic force comes into act which is governed by Coulomb's law.

Given as:

F=\frac{1}{4\pi \epsilon_0} \times \frac{q_1.q_2}{R^2}

where:

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R = radial distance between the charges.

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