Answer:
so pressure in A must be one third the pressure in B
Explanation:
We shall apply gas law to the cylinders A and B . Since their quantity are same so their no of mole will also be same .
For cylinder A
Temperature T , volume 3V , pressure P₁ , no of mole = n
so
P₁ X 3V = n R T
For cylinder B
Temperature T , volume V , pressure P₂ ,no of mole = n
so
P₂ X V = n R T
From the two equation above
P₁ X 3V = P₂ X V
P₁ = P₂ / 3
so pressure in A must be one third the pressure in B
The mechanical energy of the train is 1,451,222.53 J
The given parameters:
mass of the car, m = 5500 kg
speed of the car, v = 55 km/h = 15.278 m/s
height of the hill, h = 15 m
To find:
The mechanical energy of the train = kinetic energy + potential energy
The kinetic energy (KE) at the train at bottom hill is calculated as:
The potential energy (P.E) of the train on top hill is calculated as:
P.E = mgh
P.E = 5500 x 9.81 x 15
P.E = 809,325 J
The mechanical energy of the train = K.E + P.E
The mechanical energy of the train = 641,897.53 J + 809,325 J
The mechanical energy of the train = 1,451,222.53 J
Thus, the mechanical energy of the train is 1,451,222.53 J
Learn more here: brainly.com/question/18453987
