All categories

3 years ago

The soft underbelly of the Axis referred to

Physics

1 answer:

PIT_PIT [208]3 years ago

6 0

The soft underbelly of the axis is referred to as Italy. Hope this helps!

You might be interested in

You place an ice cube of mass 7.50×10−3kg and temperature 0.00∘C on top of a copper cube of mass 0.220 kg. All of the ice melts,

g100num [7]

Answer:

$T = 29.66 ^o C$

Explanation:

As we know that here final equilibrium temperature is 0 degree C

so we can use energy conservation here

heat given by the cube = heat absorbed by the ice

so we have

$ms \Delta T = m' L$

so here we have

$0.220(385)(T - 0) = (7.50 \times 10^{-3})(3.35 \times 10^5)$

$T = \frac{2512.5}{0.220 \times 385}$

$T = 29.66 ^o C$

5 0

3 years ago

Two blocks are connected as shown in the diagram below. Assume that the ramp is frictionless. Draw the force diagram for the blo

cluponka [151]

Answer:

diagram: see image, x-component: 84.3 N, acceleration: 4.38 m/s^2

Explanation:

(see image for further explanation)

5 0

3 years ago

what will be the acceleration due to gravity at up planet whose mass is 8 times the mass of the earth and whose radius is twice

Alexxandr [17]

Hope it cleared your doubt.

3 0

3 years ago

Physics question, help please!

vova2212 [387]

The change in potential energy when the block falls to ground is -480J.

The maximum change in kinetic energy of the ball is 480 J.

The initial kinetic energy of the ball is 0 J.

The final kinetic energy of the ball is 0.148J.

The initial potential energy of the ball is 0.187 J.

The final potential energy of the ball is 0 J.

The work done by the air resistance is 0.039 J.

<h3>Change in potential energy when the block falls to ground</h3>

ΔP.E = -mgh

ΔP.E = -Wh

ΔP.E = - 40 x 12

ΔP.E = -480 J

<h3>Maximum change in kinetic energy of the ball</h3>

ΔK.E = - ΔP.E

ΔK.E = - (-480 J)

ΔK.E = 480 J

<h3>Initial kinetic energy of the ball</h3>

K.Ei = 0.5mv²

where;

v is zero since it is initially at rest

K.Ei = 0.5m(0) = 0

<h3>Final kinetic energy</h3>

K.Ef = 0.5mv²

K.Ef = 0.5(0.0091)(5.7)²

K.Ef = 0.148 J

<h3>Initial potential energy of the ball</h3>

P.Ei = mghi

P.Ei = 0.0091 x 9.8 x 2.1

P.Ei = 0.187 J

<h3>Final potential energy</h3>

P.Ef = mghf

P.Ef = 0.0091 x 9.8 x 0

P.Ef = 0

<h3>Work done by the air resistance</h3>

W = ΔE

W = P.E - K.E

W = 0.187 J - 0.148 J

W = 0.039 J

Learn more about potential energy here: brainly.com/question/1242059

#SPJ1

<h3 />

7 0

1 year ago

A person is standing on and facing the front of a stationary skateboard while holding a construction brick. The mass of the pers

Inessa [10]

Answer:

v₁ = -0.8087 m / s

Explanation:

To solve this problem we can use the conservation of momentum, for this we define a system formed by the man, the skateboard and the brick, therefore the force during the separation is internal and the momentum is conserved

Initial instant. When they are united

p₀ = 0

Final moment. After throwing the brick

$p_{f}$ = (m_man + m_skate) v1 + m_brick v2

the moment is preserved

p₀ = p_{f}

0 = (m_man + m_skate) v₁ + m_brick v₂

v₁ = - $\frac{ m_{brick} }{m_{man} + m_{skate} } v_{2}$

the negative sign indicates that the two speeds are in the opposite direction

let's calculate

v₁ = - $\frac{2.5}{67 + 4.10} 23.0$

v₁ = -0.8087 m / s

6 0

3 years ago