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Shkiper50 [21]
2 years ago
14

If this standing wave is 48.8 meters long from end to end, what is the wavelength?

Physics
1 answer:
Mrrafil [7]2 years ago
6 0

The wavelength of a standing wave is 8.13 m.

<h3>What is a wavelength?</h3>

The distance between two successive troughs or crests is known as the wavelength. The peak of the wave is the highest point, while the trough is the lowest.

The wavelength is also defined as the distance between two locations in a wave that have the same oscillation phase.

The given data in the problem is;

String length(L)= 48.8 metere

Wavelength(λ)=?

The length of the wave having n nodes is found as;

L=nλ

Substitute the given value;

48.8 = 6λ

λ= 8.13 m

Hence, the wavelength of a standing wave is 8.13 m.

To learn more about the wavelength, refer to the link;

brainly.com/question/7143261

#SPJ1

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Properties of helium
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3 years ago
What would be the magnitude of the electric field 0.75 m from a 0.63 C master charge and what would be the force on a 0.50 C tes
bagirrra123 [75]

The magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

<h3>Electric field on the master charge</h3>

E = kq/r²

where;

  • q is magnitude of master charge
  • r is distance of separation
  • k is Coulomb's constant

E = (9 x 10⁹ x 0.63)/(0.75²)

E = 1.008 x 10¹⁰ N/C

<h3>Force on the test charge</h3>

F = Eq

where;

  • E is electric field
  • q is the test charge

F = (1.008 x 10¹⁰) x (0.5)

F = 5.04 x 10⁹ N

Thus, the magnitude of the electric field on the master charge is 1.008 x 10¹⁰ N/C, and the force on the test charge is 5.04 x 10⁹ N.

Learn more about electric field here: brainly.com/question/14372859

#SPJ1

8 0
2 years ago
A 0.850 kg block is attached to a spring with spring constant 18 N/m . While the block is sitting at rest, a student hits it wit
Sveta_85 [38]

The block's speed at the point where x=0.25A is v = 31.95 cm/s.

<h3>What is Spring constant?</h3>

The spring stiffness is quantified by the spring constant, or k. For various springs and materials, it varies. The stiffer the spring is and the harder it is to stretch, the bigger the spring constant.

question is incomplete, this is the remaining statement

What is the amplitude of the subsequent oscillations? And What is the block's speed at the point where x=0.25A?

x = Asin(wt)

v = Aw coswt

at t = 0

w = sqrt(k/m)

v = Aw

A = v/w

A = 7.17 cm

part b )

E = 1/2mv^2 + 1/2kx^2 = 1/2kA^2

mv^2 + k(1/4A)^2 = 1/2kA^2

mv^2 + kA^2/16 = kA^2

mv^2 = kA^2 - kA^2/16

mv^2 = 15kA^2/16

v^2 = 15/16 * (k/m) * A^2

v^2 = 15/16 *w^2A^2

v = sqrt(15/16) * wA

v = 31.95 cm/s

to learn more about spring constant go to -

brainly.com/question/23885190

#SPJ4

8 0
2 years ago
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