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marusya05 [52]
4 years ago
12

Explain the following behaviour of molecules water rises up in a harrow tubes but mercury which is also a liquid falls in a narr

ow tubes to level below the outside surface
Physics
1 answer:
Mandarinka [93]4 years ago
7 0

Answer: find the answer in the explanation

Explanation:

The capillarity of water molecules is different from the mercury molecules.

What is capillarity ?

This is the tendency of a liquid substance to rise in a capillary tube.

Molecules water rises up in a harrow tubes because of the force of adhesion between the water molecules and the tube molecules is greater than the force of cohesion between the water molecules. This helps water to wet the tube and rise. While mercury which is also a liquid falls in a narrow tubes to level below the outside surface because the force of cohesion between the mercury molecules is greater than the force of adhesion between the mercury molecules and the tube molecules. Mercury does not wet.

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An oak block had the following dimension, 2 cm by 2 cm and 5 cm in height. A copper block had the same dimensions. The copper bl
antiseptic1488 [7]

Answer:

ρ_body = 1000 kg / m³

Explanation:

This is an exercise in fluid mechanics, specifically we must use the Archimedean principle, which states that the thrust is equal to the weight of the dislodged liquid.

In this case let's start by finding the volume of our body

oak block

      v = l to h

       v = 0.02 0.02 0.05

       V = 2 10⁻⁵ m³

cooper block indicate that it has the same dimensions so its volume is the same, the total volume of the body is

        V_total = 4 10⁻⁵ m³

as they indicate that the body is fully submerged there is a balance between weight and thrust

          B - W = 0

the push is

          B = ρ_fluid g V_total

the body weight is

         ρ_body = M / V_total

          M = ρ_body V_total

         W = Mg

          W = ρ_body V_total g

we substitute

          ρ_fluid g V_total = ρ_body V_total g

        ρ_body = ρ_fluid

in this case the body is in equilibrium in the fluid, in case the density of the body is greater than that of the fluid, the body sinks

Therefore the average density is equal to the density of the fluid, since since it is water the density is

              ρ_body = 1000 kg / m³

8 0
3 years ago
A boy of mass 30.0 kg is sledding down a 70.0-m slope starting from rest. The slope is angled at 15.0° below the horizontal. Aft
Studentka2010 [4]

The speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

<h3>Their speed at the bottom</h3>

Apply the principle of conservation of energy,

E(up) - E(friction) = E(bottom)

mg sin(15) + ¹/₂(M + m)u² - μ(M + m)cos 15 = ¹/₂(M + m)v²

v = \sqrt{2[\frac{mgd \ sin15 \ + \frac{1}{2}(M + m)u^2 \ -\mu (M + m)g cos\ 15 }{M + m}] }

where;

  • u is the speed of the after 28 m

u = √2gh

u = √(2gL sin15)

u = √(2 x 9.8 x 28 x sin 15)

u = 11.92 m/s

v = \sqrt{2[\frac{(30)(9.8)(70) \ sin15 \ + \frac{1}{2}(30 + 50)(11.92)^2 \ - 0.12 (30 + 50)9.8 cos\ 15 }{30 + 50}] }\\\\v = 16.52 \ m/s

Thus, the speed of the boy and his friend at the bottom of the slope is 16.52 m/s.

Learn more about speed here: brainly.com/question/6504879

#SPJ1

8 0
2 years ago
if a bullet fired beneath the water, straight up, breaks through the surface at a speed of 25m/s, how high will the bullet be af
Doss [256]

Answer:

32 m and -2.4 m/s

Explanation:

Given:

v₀ = 25 m/s

t = 2.8 s

a = -9.8 m/s²

Find: Δy, v

Δy = v₀ t + ½ at²

Δy = (25 m/s) (2.8 s) + ½ (-9.8 m/s²) (2.8 s)²

Δy = 31.6 m

v = at + v₀

v = (-9.8 m/s²) (2.8 s) + 25 m/s

v = -2.44 m/s

Rounded to two significant figures, the bullet reaches a height of 32 m and a velocity of -2.4 m/s.

8 0
4 years ago
ANSWER QUICK 40 POINTSSSS
cluponka [151]

Answer:

For 6 its D

For 7 its A

For 8 its C

For 9 I think its B but Im not sure

4 0
3 years ago
Two ice skaters stand together. They push off and travel directly away from each other, the boy with a velocity of v = +0.35 m/s
DIA [1.3K]

Answer:

-0.55m/s

Explanation:

Given that: For the boy

Weight = 745N

Velocity = +0.35 m/s

Mass of the boy = ?

g = 9.81m/s^2

W = mg

745 = m×9.81

m = 75.94kg

For the girl

Given that:

Weight = 477 N

g = 9.81m/s^2

m = ?

W = mg

477 = m×9.81m/s^2

m = 48.62kg

To solve for the v of the girl, the two has to add up

48.62kg×v + 75.94kg×+0.35 m/s = 0

48.62v + 26.579 = 0

48.62v = - 26.579

v = -26.579/48.62

v = -0.5466

v = -0.55m/s

Hence, the velocity of the girl is -0.55m/s.

The negative sign is as a result of the two of them moving is opposite direction.

5 0
3 years ago
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