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marusya05 [52]
4 years ago
12

Explain the following behaviour of molecules water rises up in a harrow tubes but mercury which is also a liquid falls in a narr

ow tubes to level below the outside surface
Physics
1 answer:
Mandarinka [93]4 years ago
7 0

Answer: find the answer in the explanation

Explanation:

The capillarity of water molecules is different from the mercury molecules.

What is capillarity ?

This is the tendency of a liquid substance to rise in a capillary tube.

Molecules water rises up in a harrow tubes because of the force of adhesion between the water molecules and the tube molecules is greater than the force of cohesion between the water molecules. This helps water to wet the tube and rise. While mercury which is also a liquid falls in a narrow tubes to level below the outside surface because the force of cohesion between the mercury molecules is greater than the force of adhesion between the mercury molecules and the tube molecules. Mercury does not wet.

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In a certain region of space, a uniform electric field is in the x direction. A particle with negative charge is carried from x
Ostrovityanka [42]

Answer:

(a) increase

Explanation:

On a line graph; we have the x-axis to the positive side and the negative side .In a positive x-axis direction, the force is usually positive, vice versa the negative side as well.

The change in the potential energy of a charge field-system can be given as:

\delta U= -q(EdsCos \theta)

where;

q = positive test charge

E = Electric field

ds = displacement between thee charge positions

θ  = Angle between the electric field and the displacement.

Given that:

Charge of the particle = -q

displacement = (60.0 -20.0)cm = 40.0 cm

θ = 0

Replacing our values in the above equation, we have:

\delta U = -(-q)(60Cos 0)

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Since the potential energy of the system is positive, therefor the electric potential energy also increases.

5 0
3 years ago
What is the wavelength of the third harmonic in a 4.5-m-long pipe that is closed at one end?
lisov135 [29]

Answer:

Wavelength of sound in the pipe is 6.0 m

Explanation:

As we know that closed pipe is given to us so here at open end it will form antinode while at closed end it will form Node

Here we know that in closed pipes on odd harmonics will exist

so here for third harmonic we have

L = \frac{\lambda}{4} + \frac{\lambda}{2}

where L = length of the pipe

so we have

4.5 = \frac{3\lambda}{4}

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5 0
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A space vehicle is traveling at 2980 km/h relative to Earth when the exhausted rocket motor is disengaged and sent backward. The
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3054.4 km/h

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14900 km/h = 5v + 93

14900 - 93 = 5v

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the speed of the module = 2961.4 + 93 = 3054.4 km/h

8 0
3 years ago
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