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ivanzaharov [21]
3 years ago
7

Someone please help me will give BRAILIEST!!!!!

Physics
1 answer:
nataly862011 [7]3 years ago
3 0
It uses C. Kinetic Energy
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What is the gravitational force between two 60.0 kg people sitting 100 m<br> apart?
Finger [1]

Answer:

2.4 × 10^(-11) N

Explanation:

F = Gm²/r²

F = 6.67×10^(-11) × 60² / 100²

= 2.4×10^(-11) N

7 0
4 years ago
A stationary sub uses sonar to send a 1.18x10^3 hertz sound wave through ocean water. The reflected sound wave from the flat oce
vampirchik [111]

Answer:

a) v = 1524.7 m/s

b) T = 8.47*10^-4 s

   λ = 1.29 m

Explanation:

a) First, in order to calculate the speed of the sound wave, you take into account that the velocity is constant, then, you use the following formula:

v=\frac{d}{t}

d: distance traveled by the sound wave, which is twice the distance to the ocean bottom = 2*324 m = 648 m

t: time that sound wave takes to return to the sub = 0.425

v=\frac{648m}{0.425s}=1524.7\frac{m}{s}

hence, the speed of the sound wave is 1524.7 m/s

b) Next, with the value of the velocity of the wave you can calculate the wavelength of the wave, by using the following formula:

v=\lambda f\\\\\lambda=\frac{v}{f}

f: frequency = 1.18*10^3 Hz

\lambda=\frac{1524.7m/s}{1.18*10^3s^{-1}}=1.29m

And the period is:

T=\frac{1}{f}=\frac{1}{1.18*10^3s^{-1}}=8.47*10^{-4}s

hence, the wavelength and period of the sound wave is, respectively, 1.29m and 8.47*10^-4 s

5 0
3 years ago
A 47.4 kg student runs down the sidewalk and jumps with a horizontal speed of 42 m/s onto a stationary skateboard
Tpy6a [65]

Answer:

3 kg

Explanation:

Momentum before = momentum after

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

After jumping on the skateboard, the student and the skateboard have the same velocity, so v₁ = v₂.

m₁u₁ + m₂u₂ = (m₁ + m₂) v

(47.4 kg) (4.2 m/s) + m (0 m/s) = (47.4 kg + m) (3.95 m/s)

m = 3 kg

8 0
4 years ago
If you push twice as hard against a stationary brick wall, the amount of work you do
Alecsey [184]

Answer:

Zero

Explanation:

The work done on an object is given by:

W=Fd cos \theta

where

F is the force applied on the object

d is the displacement of the object

\theta is the angle between the direction of the force and the displacement

In this problem, you are pushing again a stationary wall: this means that the walls does not move. As a result, the displacement is zero: d=0. Therefore, the work done is also zero: W=0.

8 0
3 years ago
Three wires meet at a junction. wire 1 has a current of 0.40 aa into the junction. the current of wire 2 is 0.73 aa out of the j
Mnenie [13.5K]

The magnitude of the current in wire 3 is (I₃)= 0.33A

<h3>How to calculate the value of the magnitude of the current in wire 3 ?</h3>

To calculate the magnitude of the current in wire 3 we are using the Kirchhoff’s current law,

I₁ + I₂ + I₃ = 0

Where we are given,

I₁ = current in wire 1

=0.40 A.

I₂ = current in wire 2

= -0.73 A.

We have to calculate the magnitude of the current in wire 3, I₃

Now we put the known values in above equation, we get,

I₁ + I₂ + I₃ = 0

Or, I₃ = -.(I₁ + I₂)

Or, I₃ = -.(0.40 - 0.73)

Or, I₃ = 0.33 A

From the above calculation, we can conclude that the current in wire 3 is  I₃ = 0.33 A

Learn more about current:

brainly.com/question/25537936

#SPJ4

7 0
1 year ago
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