<span>a.{x | x is a real number such that x^2 = 1}
x^2 = 1 => x = +/- 1
=> {-1, 1} <------ answer
b.{x | x is a positive integer less than 12}
1 ≤ x < 12 => {1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11} <------ answer
c.{x | x is the square of an integer and x < 100}
x = n^2 < 100 => n^2 - 100 < 0
=> (n - 10) (n + 10) < 0
=> a) n - 10 > 0 and n + 10 < 0 => n > 10 and n < - 10 which is not possible
b) n - 10 < 0 and n + 10 > 0 => n < 10 and n > - 10 => - 10 < n < 10
=> n = { - 9, - 8, - 7, - 6, - 5, -4, -3, -2, -1, 0, 1, 2, 3, 4, 5, 6, 7, 8, 9}
=> x = {0, 1, 4, 9, 16, 25, 36, 49, 64, 81} <---- answer
d.{x | x is an integer such that x^2 = 2}
</span>
x = {∅ } because x is √2 which is not an interger but an irrational number
=> Answer: { ∅ }
Answer:
1) h(t) = -5(t-3)^2
2) The ball reaches the highest point at 3 seconds.
Step-by-step explanation:
OK. So for this question, I recommend to rewite using vertex form since the answer is given in a more concise manner than using factored.
First Step:
h(t) = -5t^2+30t
= -5(t^2-6t)
= -5(t^2-6t+9)+45
= -5(t-3)^2+45
Second Step:
The vertex form reveals the vertex to be at (3, 45).
Therefore, the ball reaches the highest point at 3 seconds.
Answer:
x = 27
Step-by-step explanation:
(whole secant) * (external part) = (tangent)^2
(x+48)* 48 = 60^2
(x+48)* 48 = 3600
Divide each side by 48
x+48 =75
Subtract 48 from each side
x = 75-48
x=27