Simplify the expression (2^-4)^-2

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pickupchik [31]

Answer: sure

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

Which of the following is a area of the special trepezoid if ab=19,cd=19 and the height is 14

tankabanditka [31]

As, Opposite side of Special trapezoid is equal.So, it will be a Parallelogram.

ab=c d= 19 units

Height of Trapezoid = 14 units

Area of Trapezoid = $\frac{1}{2} \times {\text{Sum of parallel sides}} \times {\text{Perpendicular Distance between them}}$

$=\frac{1}{2}\times (19+19) \times 14\\\\ =\frac{1}{2} \times 38 \times 14\\\\ = 19 \times 14\\\\= 266$

So, Area of Trapezoid = 266 square units

You, can use the formula for finding the area of parallelogram,which is = Base on which perpendicular is drawn × Length of Altitude

= 19 × 14

= 266 square units

5 0

3 years ago

SOMEONE PLEASE HELP ASAP!!!!!

Margaret [11]

Answer:

x = 1

y = 1

Step-by-step explanation:

System of Equations

We are given the system of equations:

2x + y = 3

x = 2y - 1

Substituting x in the first equation:

2(2y - 1) + y = 3

Operating:

4y - 2 + y = 3

5y = 3 + 2

y = 5/5 = 1

y = 1

Since:

x = 2y - 1

Then:

x = 2(1) - 1

x = 1

Solution:

x = 1

y = 1

7 0

3 years ago

Given x(y + 2) = 3x + y, express y in terms of x.

vodka [1.7K]

Answer:

y = $\frac{x}{x-1}$

Step-by-step explanation:

Given

x(y + 2) = 3x + y ← distribute parenthesis on left side

xy + 2x = 3x + y ( subtract 2x from both sides )

xy = x + y ( subtract y from both sides )

xy - y = x ← factor out y from each term on the left side )

y(x - 1) = x ← divide both sides by (x - 1)

y = $\frac{x}{x-1}$

6 0

3 years ago

A box in a supply room contains 24 compact fluorescent lightbulbs, of which 8 are rated 13-watt, 9 are rated 18-watt, and 7 are

Marrrta [24]

Answer:

a) There is 17.64% probability that exactly two of the selected bulbs are rated 23-watt.

b) There is a 8.65% probability that all three of the bulbs have the same rating.

c) There is a 12.45% probability that one bulb of each type is selected.

Step-by-step explanation:

There are 24 compact fluorescent lightbulbs in the box, of which:

8 are rated 13-watt

9 are rated 18-watt

7 are rated 23-watt

(a) What is the probability that exactly two of the selected bulbs are rated 23-watt?

There are 7 rated 23-watt among 23. There are no replacements(so the denominators in the multiplication decrease). Then can be chosen in different orders, so we have to permutate.

It is a permutation of 3(bulbs selected) with 2(23-watt) and 1(13 or 18 watt) repetitions. So

$P = p^{3}_{2,1}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = \frac{3!}{2!1!}*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 3*\frac{7}{24}*\frac{6}{23}*\frac{17}{22} = 0.1764$