An extraterrestrial civilisation lives on a planet with a very elliptical orbit. Additionally, thousands of large asteroids orbi
t their solar system. The civilisation uses the light from their home star to count the number of asteroids in the direct line between the star and their planet. For a first measurement, they count the asteroids for 60 days and detect 1000 objects. Several months later, they start a second measurement: This time, they count for 80 days. How many asteroids will they detect during the second measurement? Explain why. (Note: Assume that the asteroids are homogeneously distributed in their solar system.)
i will mark as a brainiest please help me as soon 
i will mark as a brainiest please help me as soon
2 answers:
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Answer:
Assuming that both mass here move horizontally on a frictionless surface, and that this spring follows Hooke's Law, then the mass of would be four times that of
.
Explanation:
In general, if the mass in a spring-mass system moves horizontally on a frictionless surface, and that the spring follows Hooke's Law, then
.
Here's how this statement can be concluded from the equations for a simple harmonic motion (SHM.)
In an SHM, if the period is , then the angular velocity of the SHM would be
.
Assume that the mass starts with a zero displacement and a positive velocity. If represent the amplitude of the SHM, then the displacement of the mass at time
would be:
.
The velocity of the mass at time would be:
.
The acceleration of the mass at time would be:
.
Let represent the size of the mass attached to the spring. By Newton's Second Law, the net force on the mass at time
would be:
,
Since it is assumed that the mass here moves on a horizontal frictionless surface, only the spring could supply the net force on the mass. Therefore, the force that the spring exerts on the mass will be equal to the net force on the mass. If the spring satisfies Hooke's Law, then the spring constant will be equal to:
.
Since , it can be concluded that:
.
For the first mass , if the time period is
, then the spring constant would be:
.
Similarly, for the second mass , if the time period is
, then the spring constant would be:
.
Since the two springs are the same, the two spring constants should be equal to each other. That is:
.
Simplify to obtain:
.
Complete Question
The complete question is shown on the first uploaded image
Answer:
The acceleration would be
Explanation:
The objective of this solution is to obtain the acceleration of the particle
Now looking at Newton law which is mathematically represented as
Where F is the force experience by a particle
m is the mass of the particle
a is the acceleration of the particle
And also this force is equivalent to magnetic force in a magnetic field which is mathematically represented as
Where q is the charge of the particle
v is the velocity of the charge
B is the magnetic field the charge is under it influence
Now equating this two formulas
Making a the subject we have
In the question the direction of the is in the positive x-axis which is hence the direction would be in the
direction
So substituting for B
Substituting for v and
for q
According to vector multiplication
So
