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Gnom [1K]
4 years ago
13

What constant acceleration, in SI units, must a car have to go from zero to 60 mph in 10 s? How far has the car traveled when it

reaches 60 mph? Give your answer both in SI units and in feet.\
Physics
1 answer:
nalin [4]4 years ago
7 0

Answer:

Explanation:

initial velocity, u = 0

final velocity, v = 60 mph = 26.8 m/s

time t = 10 s

Let a be the acceleration and s be he distance traveled.

Use first equation of motion

v = u + a t

26.8 = 0 +  a x 10

a = 2.68 m/s

Use second equation of motion

s = ut + 1/2 at²

s = 0 + 0.5 x 2.68 x 10 x 10

s = 134 m

As, 1 m = 3.28 ft

So, s = 134 x 3.28 ft

s = 439.6 ft

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Which of the following objects conducts heat the best?
JulijaS [17]
I think its C. because metal is a good conductor of heat

I hope this helps ^-^

let me know if im wrong
4 0
4 years ago
Read 2 more answers
Select the correct expression that gives the block's acceleration at a displacement x from the equilibrium position. Note that x
Tcecarenko [31]

Answer:

the correct is d

a= - k/m x

Explanation:

I got it correct

6 0
4 years ago
In a particular region, there is a uniform magnetic field with a magnitude of 2.00 T. You take a particle with a charge of +6.00
expeople1 [14]

Answer:

a) 1.68 N b) 0 c) 14.5º

Explanation:

a)

  • The force on a charge moving in a magnetic field, is a vector perpendicular to the plane defined by the velocity of the charge and the magnetic field.
  • The magnitude of the force F is given by the following expression:

       F = q*v*B*sin\theta (1)

  • where q= magnitude of the charge of the particle, v=velocity of the particle, B= magnitude of the magnetic field, and θ= angle between v and B.
  • Replacing by the known values in (1) we have:

       F = q*v*B*sin\theta (1) = 6.00e-6C*1.40e5m/s*2T*sin\theta=\\ \\ F= 1.68N*sin\theta

  • The maximum possible value of F happens when sin θ =1
  • This means that v and B are perpendicular each other (in the same plane)
  • So, Fmax = 1.68 N

b)

  • If the maximum possible value of F happens when sin θ = 1, the minimum possible is when sin θ = 0.
  • In this case, when v  and B are parallel each other, the force is just 0.

c)

  • If the force is 0.25 of the maximum possible, (which is when sin θ =1), this means that sin θ = 0.25, as it can be seen below:

       F_{\theta} = q*v*B*sin \theta = 0.25*Fmax\\ F_{\theta} = q*v*B*sin\theta= 0.25 (q*v*B*sin 90) \\ sin \theta = 0.25

       \theta = sin^{-1} (0.25) =14.5 deg

  • The angle between the velocity v and the magnetic field B is 14.5º.
3 0
4 years ago
The magnetic flux through a coil of wire containing two loops changes at a constant rate from -58 wb to 38 wb in 0. 34 s. What i
german

The emf induced in the coil is -5.65 V

<h3>Induced emf in coil</h3>

The induced emf in the coil is given by ε = -NΔΦ/Δt where

  • ΔΦ = change in magnetic flux Φ₂ - Φ₁ where
  • Φ₁ = initial magnetic flux = -58 Wb and
  • Φ₂ = final magnetic flux = 38 Wb and and
  • Δt = change in time = t₂ - t₁ where
  • t₁ = initial time = 0 s and
  • t₂ = final time = 34 sand
  • N = number of loops of coil = 2

Since ε = -NΔΦ/Δt

ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)

Substituting the values of the variables into the equation, we have

ε = -N(Φ₂ - Φ₁)/(t₂ - t₁)

ε = -2(38 Wb - (-58 Wb))/(34 s - 0 s)

ε = -2(38 Wb + 58 Wb)/(34 s - 0 s)

ε = -2(96 Wb)/34 s

ε = -192 Wb/34 s

ε = -5.65 Wb/s

ε = -5.65 V

So, the emf induced in the coil is -5.65 V

Learn more about induced emf in coil here:

brainly.com/question/13051297

6 0
3 years ago
A very long line of charge with charge per unit length +8.00 μC/m is on the x-axis and its midpoint is at x = 0. A second very l
artcher [175]

Answer:

at y=6.29 cm the charge of the two distribution will be equal.

Explanation:

Given:

linear charge density on the x-axis, \lambda_1=8\times 10^{-6}\ C

linear charge density of the other charge distribution, \lambda_2=-6\times 10^{-6}\ C

Since both the linear charges are parallel and aligned by their centers hence we get the symmetric point along the y-axis where the electric fields will be equal.

Let the neural point be at x meters from the x-axis then the distance of that point from the y-axis will be (0.11-x) meters.

<u>we know, the electric field due to linear charge is given as:</u>

E=\frac{\lambda}{2\pi.r.\epsilon_0}

where:

\lambda= linear charge density

r = radial distance from the center of wire

\epsilon_0= permittivity of free space

Therefore,

E_1=E_2

\frac{\lambda_1}{2\pi.x.\epsilon_0}=\frac{\lambda_2}{2\pi.(0.11-x).\epsilon_0}

\frac{\lambda_1}{x} =\frac{\lambda_2}{0.11-x}

\frac{8\times 10^{-6}}{x} =\frac{6\times 10^{-6}}{0.11-x}

x=0.0629\ m

∴at y=6.29 cm the charge of the two distribution will be equal.

9 0
3 years ago
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