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3 years ago

Where do most comets in our solar system come from?

Physics

2 answers:

Serggg [28]3 years ago

8 0

The Oort Cloud is where most of our comets come from.

Tasya [4]3 years ago

6 0

Answer:

the Kuiper Belt, and the Oort Cloud

Explanation:

Comets spend most of their lives far away from the sun in the distant reaches of the solar system. They primarily originate from two regions. The Kuiper Belt, and the Oort Cloud

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Which of the following depicts xylem?

BlackZzzverrR [31]

C is the right image for that biological process.

8 0

3 years ago

You are given a sample of metal and asked to determine its specific heat. You weight the sample and find that its weight is 28.4

lidiya [134]

Answer:

The samples specific heat is 14.8 J/kg.K

Explanation:

Given that,

Weight = 28.4 N

Suppose, heat energy $E=1.25\times10^{4}\ J$

Temperature = 18°C

We need to calculate the samples specific heat

Using formula of specific heat

$Q=mc\Delta T$

$c=\dfrac{Q}{m\Delta T}$

Where, m = mass

c = specific heat

$\Delta T$ = temperature

Q = heat

Put the value into the formula

$c=\dfrac{1.25\times10^{4}}{\dfrac{28.4}{9.8}\times(18+273)}$

$c=14.8\ J/kg. K$

Hence, The samples specific heat is 14.8 J/kg.K

8 0

3 years ago

Water is leaking out of an inverted conical tank at a rate of 10,500 cm3/min at the same time that water is being pumped into th

satela [25.4K]

The tank has a volume of $\dfrac\pi3R^2H$ , where $H=6\,\rm m$ is its height and $R=\dfrac d2=2\,\rm m$ is its radius.

At any point, the water filling the tank and the tank itself form a pair of similar triangles (see the attached picture) from which we obtain the following relationship:

$\dfrac26=\dfrac rh\implies r=\dfrac h3$

The volume of water in the tank at any given time is

$V=\dfrac\pi3r^2h$

and can be expressed as a function of the water level alone:

$V=\dfrac\pi3\left(\frac h3\right)^2h=\dfrac\pi{27}h^3$

Implicity differentiating both sides with respect to time $t$ gives

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9h^2\,\dfrac{\mathrm dh}{\mathrm dt}$

We're told the water level rises at a rate of $\dfrac{\mathrm dh}{\mathrm dt}=20\,\frac{\rm cm}{\rm min}$ at the time when the water level is $h=2\,\mathrm m=200\,\mathrm{cm}$ , so the net change in the volume of water $\dfrac{\mathrm dV}{\mathrm dt}$ can be computed:

$\dfrac{\mathrm dV}{\mathrm dt}=\dfrac\pi9(200\,\mathrm{cm})^2\left(20\,\dfrac{\rm cm}{\rm min}\right)=\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}$

The net rate of change in volume is the difference between the rate at which water is pumped into the tank and the rate at which it is leaking out:

$\dfrac{\mathrm dV}{\mathrm dt}=(\text{rate in})-(\text{rate out})$

We're told the water is leaking out at a rate of $10,500\,\frac{\mathrm{cm}^3}{\rm min}$ , so we find the rate at which it's being pumped in to be

$\dfrac{800,000\pi}9\,\dfrac{\mathrm{cm}^3}{\rm min}=(\text{rate in})-10,500\,\dfrac{\mathrm{cm}^3}{\rm min}$

$\implies\text{rate in}\approx289,753\,\dfrac{\mathrm{cm}^3}{\rm min}$

4 0

3 years ago

When hot and cold air meet, the hot air rises to the top. Which process causes the hot air to rise?

sweet-ann [11.9K]

I took this test before, aren't there answer choices? :)

5 0

3 years ago

Read 2 more answers

What’s the frequency for problem #10?

Kaylis [27]

The answers penciled in on the sheet are fine ... 1500 Hz and 0.0006 sec.

If you want to get super-technical about it, you could count the number of full cycles on the WHOLE graph, from one side to the other. At the right end, near 0.01 sec, you can notice an extra 1/4 of a cycle there. So it's actually 15 and 1/4 cycles in 0.01 sec.

That makes the frequency (15.25 cycles) / (0.01 sec) = 1,525 Hz .

and the period ( second / 1525) = 0.000656... second.

But I think it would be OK if you didn't do that, and just call it 1500 Hz and 0.0006s.

The difference is only 1.6% , and the engineer in me says that's not enough to worry about.

3 0

3 years ago