Which of the following chemical reactions represents an acid-base reaction?

How many grams of chlorine gas can be produced from the decomposition of 73.4

ser-zykov [4K]

1) first, we have to convert the grams to moles of AuCl3 using the molar mass of the molecule.

molar mass of AuCl3= 197 + (35.5 x 3)= 303.5 g/mol

73.4 g (1 mol AuCl3/ 303.5 g)= 0.242 moles

2) now. let's convert moles of AuCl3 to moles of chlorine gas (Cl2) using the mole-mole ratio

0.242 mol AuCl3 (3 mol Cl2/ 2 mol AuCl3)= 0.363 mol Cl2

3) finally, we convert moles to grams using the molar mass of Cl2.

molar mass of Cl2 = 35.5 x 2= 71.0 g/mol

0.363 mol Cl2 ( 71.0 g/ 1 mol)= 25.8 grams

6 0

3 years ago

A gas has a pressure of 7.01 atm at 227°C. What will its temperature be if the pressure is increased to 12.1 atm and volume is h

kirill [66]

Answer:

The temperature of the gas will be 590.05 C.

Explanation:

Gay-Lussac's law can be expressed mathematically as follows:

$\frac{P}{T} =k$

Where P= Pressure, T = temperature, K = Constant

This law indicates that the ratio between pressure and temperature is constant.

This law indicates that, as long as the volume of the container containing the gas is constant, as the temperature increases, the gas molecules move faster. Then the number of shocks against the walls increases, that is, the pressure increases. That is, the gas pressure is directly proportional to its temperature.

In short, when there is a constant volume, as the temperature increases, the gas pressure increases. And when the temperature decreases, gas pressure decreases.

It is desired to study two different states, an initial state and an final state. You have a gas that is at a pressure P1 and at a temperature T1 at the beginning of the experiment. When the temperature varies to a new T2 value, then the pressure will change to P2, and the following will be true:

$\frac{P1}{T1} =\frac{P2}{T2}$

In this case:

P1= 7.01 atm
T1= 227 C= 500 K (being 0 C= 273 K)
P2= 12.1 atm
T2= ?

Replacing:

$\frac{7.01 atm}{500 K} =\frac{12.1 atm}{T2}$

Solving:

$T2=12.1 atm*\frac{500 K}{7.01 atm}$

T2= 863.05 K= 590.05 C

The temperature of the gas will be 590.05 C.

6 0

3 years ago

A chemist identifies compounds by identifying bright lines in their spectra. She does so by heating the compounds until they glo

allsm [11]

Answer:

PART A: 412.98 nm

PART B: 524.92 nm

Explanation:

The equation below can be used for a diffraction grating of nth order image:

n*λ = d*sinθ $_{n}$

Therefore, for first order images, n = 1 and:

λ = d*sinθ $_{1}$ .

The angle θ $_{1}$ can be calculated as follow:

tan θ $_{1}$ = 9.95 cm/15.0 cm = 0.663 and

θ $_{1}$ = $tan^{-1}$ (0.663) = 33.56°

Thus: d =λ/sin θ $_{1}$ = 461/sin 33.56° = 833.97 nm

PART A:

For a position of 8.55 cm:

tan θ $_{1}$ = 8.55 cm/15.0 cm = 0.57 and

θ $_{1}$ = $tan^{-1}$ (0.57) = 29.68°

Therefore:

λ =d*sin θ $_{1}$ = 833.97*sin 29.68° = 412.98 nm

PART B:

For a position of 12.15 cm:

tan θ $_{1}$ = 12.15 cm/15.0 cm = 0.81 and

θ $_{1}$ = $tan^{-1}$ (0.81) = 39.01°

Therefore:

λ =d*sin θ $_{1}$ = 833.97*sin 39.01° = 524.92 nm

6 0

3 years ago

A teacher mixed zinc with hydrogen chloride in a flask and quickly attached a ballon over the mouth of the flask what most likel

USPshnik [31]

Probably inflated the balloon due to the pressure created inside?

8 0

3 years ago

Which statement is true regarding methane and ammonia?

sukhopar [10]

The options for given question are as follow,

1) Methane molecules show hydrogen bonding.
2) Ammonia molecules show hydrogen bonding. 
3) Methane has stronger hydrogen bonding than ammonia. 
4) Both the compounds do not show hydrogen bonding. 
5) Both the compounds have strong hydrogen bonding.

Answer:
Correct answer is Option-2 (Ammonia molecules show hydrogen bonding).

Explanation:
Hydrogen bond interactions are formed when a partial positive hydrogen atom attached to most electronegative atom of one molecule interacts with the partial negative most electronegative element of another molecule. So, in Ammonia hydrogen gets partial positive charge as nitrogen is highly electronegative. While the C-H bond in Methane is non-polar and fails to form hydrogen bond interactions.

6 0

3 years ago

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