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julia-pushkina [17]
3 years ago
6

Heptane and water do not mix, and heptane has a lower density (0.684 g/mL.) than water (1.00 g/

Chemistry
1 answer:
Brrunno [24]3 years ago
7 0

Answer:

Explanation:

volume of heptane= mass / density

volume of heptane = 37. 8 / .684

= 55.26 mL

volume of water  = 34.7  / 1

= 34.7 mL or cc.

If l₁ be the length of heptane layer in the graduated cylinder

volume = cross sectional area x length or height  of layer

π r² x l where r is radius of bore of the cylinder  , l is height of liquid inside cylinder .

for heptane

π r² x l₁ =  55.26

3.14 x 1.54² x l₁ = 55.26

l₁ = 7.42 cm

for water

π r² x l₂ =   34.7

3.14 x 1.54² x l₂ = 34.7

l₂ = 4.65  cm

Combined height = l₁ + l₂

= 7.42 + 4.65

= 12.07 cm .

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How is beryllium similar to calcium?<br>​
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Which aqueous solution has the highest boiling point at standard pressure?(1) 1.0 M KC1(aq) (3) 2.0 M KCl(aq)(2) 1.0 M CaC12(aq)
miss Akunina [59]

Answer:

(4) 2.0 M CaCl₂(aq).

Explanation:

  • Adding solute to water elevates the boiling point.
  • The elevation in boiling point (ΔTb) can be calculated using the relation:

<em>ΔTb = i.Kb.m,</em>

where, ΔTb is the elevation in boiling point.

i is the van 't Hoff factor.

  • van 't Hoff factor is the ratio between the actual concentration of particles produced when the substance is dissolved and the concentration of a substance as calculated from its mass. For most non-electrolytes dissolved in water, the van 't Hoff factor is essentially 1.

Kb is the molal elevation constant of water.

m is the molality of the solution.

<u><em>(1) 1.0 M KCl(aq):</em></u>

i for KCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

suppose molarity = molality, m = 1.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (2)(Kb)(1.0 m) = 2(Kb).

<u><em>(2) 2.0 M KCl(aq):</em></u>

i for KCl = no. of particles produced when the substance is dissolved/no. of original particle = 2/1 = 2.

suppose molarity = molality, m = 2.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (2)(Kb)(2.0 m) = 4(Kb).

<u><em>(3) 1.0 M CaCl₂(aq):</em></u>

i for CaCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

suppose molarity = molality, m = 1.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (3)(Kb)(1.0 m) = 3(Kb).

<u><em>(4) 2.0 M CaCl₂(aq):</em></u>

i for CaCl₂ = no. of particles produced when the substance is dissolved/no. of original particle = 3/1 = 3.

suppose molarity = molality, m = 2.0 m,

∴ ΔTb for (1.0 M KCl) = i.Kb.m = (3)(Kb)(2.0 m) = 6(Kb).

  • <em>So, the aqueous solution has the highest boiling point at standard pressure is: (4) 2.0 M CaCl₂(aq).</em>

<em></em>

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True or False
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Answer:

I believe its True

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