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podryga [215]
3 years ago
14

Bonus: A runner has a speed of 25 m/s. They see the finish line and speed up to 30 m/s. This happens in 5

Physics
1 answer:
Charra [1.4K]3 years ago
5 0
A = (v - u) / t
a = (30 - 25) / 5
a = 5/5
a = 1m/s/s

F = ma
F = 75 x 1
F = 75N
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A gardener pushes a shovel into the ground with a force of 75 N. The angle of the shovel to the ground is 80 degrees. What is th
jok3333 [9.3K]

Answer:

B

Explanation:

Resolve the 75N force into 2 components; horizontal and vertical. And remember that there is no acceleration in the downward direction, so apply Newton's second law and equate it to 0.

7 0
3 years ago
An incompressible fluid is flowing through a horizontal pipe with a constriction. The velocity of the fluid in the wide section
lapo4ka [179]

The Bermoulli's  equation allows us to find the pressure in the narrow part of the pipe through which water circulates is:

             P = 500 Pa

Bernoulli's equation is the work-energy relationship for fluids that are liquids and gases.

           P_1 + \frac{1}{2} \rho v_1^2 + \rho g y_1 = P2 +  \frac{1}{2} \rho v_2^2 + \rho g y_2

Where the subscripts 1 and 2 represent points of interest, P is the pressure, ρ the density of the fluid, v the velocity and y the height.

They indicate that the pipe is horizontal, that the pressure in the wide part P₁ = 200 kPa and the velocity is v₁ = 5 m / s and in the narrow part v₂=8.00 m/s, see attached.

Since the pipe is horizontal y₁ = y₂

           P₁ + ½ ρ v₁² = P₂ + ½ ρ v₂²

           P₂ = P₁ + ½ ρ (v₁² - v₂²)

Let's calculate

          P₂ = 200 10² + ½ ρ (5² - 8²)

          P₂ = 2 10⁴ - 19.5 ρ

For a specific calculation the value of the density of the fluid is needed, suppose that the fluid is water ρ = 1000 kg / m³

           P₂ = 2 10² - 19.5 1000

           P₂ = 500 Pa

In conclusion using the Bermoulli equation we can find the pressure in the narrow part of the pipe through which water circulates is:  

             P = 500 Pa

Learn more here: brainly.com/question/9506577

3 0
3 years ago
A baseball is thrown at an angle of 25 degrees relative to the ground at a speed of 23 m/s. If the ball was caught 42 m from the
ExtremeBDS [4]

Answer:

a) v_{0y} = 9.72 m/s

b) v_{0x} = 20.85 m/s

c) t = 2.01 s

d) h_{max} = 4.82 m

Explanation:

a) The initial vertical velocity is given by:

v_{0y} = v*sin(\theta)

Where:

θ: 25°

v: is the magnitude of the speed = 23 m/s

v_{0y} = 23 m/s*sin(25) = 9.72 m/s

b) The initial horizontal velocity can be calculated as follows:

v_{0x} = v*cos(\theta) = 23 m/s*cos(25) = 20.85 m/s

c) The flight time can be calculated using the following equation:

v_{0x} = \frac{x}{t}

Where:

x: is the total distance = 42 m

t = \frac{x}{v_{0x}} = \frac{42 m}{20.85 m/s} = 2.01 s

d) The maximum height is given by:

v_{fy}^{2} = v_{0y}^{2} - 2gh_{max}

Where:

v_{fy}: is the final vertical velocity =0 (at the maximum heigth)

g: is the gravity = 9.81 m/s²

h_{max} = \frac{v_{0y}^{2}}{2g} = \frac{(9.72 m/s)^{2}}{2*9.81 m/s^{2}} = 4.82 m

I hope it helps you!                                  

7 0
3 years ago
A truck weighs 500 N on Earth. What's the mass of the truck?
Jobisdone [24]
The answer is 50 kg plz mark as brainliest
3 0
3 years ago
Read 2 more answers
PLease Help!
scoundrel [369]

Answer:

Option A is the correct answer.

Explanation:

The instantaneous acceleration = Change in velocity in velocity/Time taken

The slope of the graph should give instantaneous acceleration.

 Slope of a graph = Change in value of Y -axis / Change in values of X -axis

 Comparing both the equations

   Change in value of Y -axis = Change in velocity in velocity

   Change in values of X -axis = Time taken

So velocity values should be on the Y axis and Time values should be on the X axis.

Option A is the correct answer.

8 0
4 years ago
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