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fgiga [73]
3 years ago
11

How do wavelength and amplitude differ in simple waves?

Physics
2 answers:
Deffense [45]3 years ago
7 0

Answer:

wavelength refer to the wave on the peak the next amplitude of height of measured from the pic to the throw the wavelength measured from peak to peak

Marina CMI [18]3 years ago
5 0

Answer:

The amplitude measures the height of the crest of the wave from the midline. The wavelength measures the horizontal distance between cycles.

Explanation:

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A cyclist and his bicycle have a combined mass of 88 kg and a combined
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2. Explain brightness of light using the wave model of light.
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A pizza delivery driver must make three stops on her route. She will first leave the restaurant and travel 4 km due north to the
topjm [15]
<h2>5.3 km</h2>

Explanation:

       This question involves continuous displacement in various directions. When it becomes difficult to imagine, vector analysis becomes handy.

       Let us denote each of the individual displacements by a vector. Consider the unit vectors \vec{i}\textrm{ and }\vec{j} as the unit vectors in the direction of East and North respectively.

       By simple calculations, we can derive the unit vectors \vec{j},\frac{-\vec{i}-\vec{j}}{2}\textrm{ and }\frac{-\frac{1}{2}\vec{i}+\frac{\sqrt{3}}{2}\vec{j}}{2} in the directions North, 45^{o} South of West and 60^{o} North of West respectively.

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       Displacement vector = 4(\vec{j})+6(\frac{-\vec{i}-\vec{j}}{2})+5(\frac{-\frac{1}{2}\vec{i}+\frac{\sqrt{3}}{2}\vec{j}}{2})=-4.25\vec{i}+3.165\vec{j}

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4 0
3 years ago
A rock is suspended by a light string. When the rock is in air, the tension in the string is 43.8 N . When the rock is totally i
sergeinik [125]

Answer:

Density of unknown liquid is 2047 kg/m^3

Explanation:

When rock is suspended in air then the weight of the rock is counter balanced by the tension force in the string

So here we have

T = mg = 43.8 N

now when the rock is immersed in water then the tension in the string is and buoyancy force due to water is counter balanced by the weight of the object

so here we have

T_1 + F_b = mg

31.3 + F_b = 43.8

F_b = 43.8 - 31.3 = 12.5 N

now we have

(1000)V(9.81) = 12.5

V = 1.27 \times 10^{-3} m^3

now when the rock is immersed into other liquid then we have

T_2 + F_b' = mg

18.3 + F_b' = 43.8

F_b' = 25.5 N

now we have

\rho(1.27 \times 10^{-3})(9.81) = 25.5

\rho = 2047 kg/m^3

4 0
3 years ago
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