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kiruha [24]
3 years ago
6

A disk of radius R (Fig. P25.73) has a nonuniform surface charge density s 5 Cr, where C is a constant and r is measured from th

e center of the disk to a point on the surface of the disk. Find (by direct integration) the electric potential at P.
Physics
1 answer:
algol [13]3 years ago
4 0

Answer:

Explanation:

dV = k (dq)/d

dV = k (sigma da)/d

dV = k (5 C r (r dr d(phi)))/d

d = sqrt(r^2 + x^2)

dV = 5 k C (r^2/sqrt(r^2+x^2)) dr d(phi)

==> V = int{5 k C (r^2/sqrt(r^2+x^2)) dr d(phi)} ; from r=0 to r=R and phi=0 to phi=2pi

==> V = 5 k C int{(r^2/sqrt(r^2+x^2)) dr d(phi)} ; from r=0 to r=R and phi=0 to phi=2pi

==> V = 5 k C (2 pi) int{(r^2/sqrt(r^2+x^2)) dr} ; from r=0 to r=R

==> V = 5 k C (2 pi) (1/2) (R sqrt(R^2+x^2) - x^2 ln(sqrt(r^2+x^2) + r) + x^2 Ln(x))

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What mean by expansion effect of heat<br>​
pishuonlain [190]

Answer:

Explanation:

-Cambio de temperatura

Al calentar un cuerpo la temperatura aumenta

Es el efecto más inmediato del calor, el aumento de la temperatura. Al calentar un cuerpo, es habitual, aunque no siempre, que el cuerpo aumente de temperatura. El aumento dependerá de la cantidad de calor que se suministra, del tipo de sustancia y de su cantidad.

-Dilatación

Cuando un objeto se calienta, su volumen aumenta. Este fenómeno se llama dilatación térmica. Por el contrario, cuando un objeto se enfría, su volumen disminuye, debido a la contracción térmica.

Cuando se calienta un cuerpo, además de cambiar de estado o variar su temperatura, también cambia su tamaño, se dilata.

Por ejemplo, los puentes no se construyen de una única pieza, sino que suelen presentar uno o varios cortes longitudinales, las llamadas juntas de dilatación. Si no existieran esas juntas, los cambios de longitud del puente entre el invierno y el verano o entre el día y la noche acabarían por romperlo.

La dilatación de un cuerpo dependerá del aumento de temperatura que experimente, de su tamaño y de la sustancia de que esté hecho. Cuanto más aumente la temperatura más aumentará su tamaño, lo mismo que cuanto mayor sea, mayor se hará.

Todos los cuerpos, ya sean sólidos, líquidos o gaseosos, varían su tamaño cuando intercambian calor con otro cuerpo.

-Cambios de estado:

Si una sustancia modifica el estado de sólido, líquido o gaseoso, se produce un cambio de estado. Un cambio de estado es una modificación en la forma en que se disponen las partículas que constituyen una sustancia.

El estado en que se encuentre un cuerpo depende de la presión a la que está sometido y de su temperatura. Para cambiar su estado se debe modificar alguna de estas variables, o ambas. Al elevar la temperatura de una sustancia sólida, aumenta la agitación de sus partículas.

5 0
3 years ago
Read 2 more answers
A pair of adult nitwits sit balanced on a teeter totter type device. One of them, whose mass is 54.2 kg, is 1.20 m from the poin
andreev551 [17]

Answer:

The mass of the second person is 28.91 kg

Explanation:

Given;

mass of the first adult, m₁ = 54.2 kg

distance of the first adult from the point of balance, x = 1.20 m

mass of the second adult, = m₂

distance of the second adult from the point of balance, y = 2.25 m

Taking moment about the point of balance, we will have

m₁x = m₂y

54.2 x 1.2 = 2.25y

2.25y = 65.04

y = 65.04/2.25

y = 28.91 kg

Therefore, the mass of the second person is 28.91 kg

3 0
4 years ago
Read 2 more answers
As plates move, large blocks of crust ___ along the faults
seraphim [82]

Answer:

move

Explanation:

i think that is it

as plates move large blocks of crust move along the faults

4 0
3 years ago
A race car travels on a circular track at an average rate of 125 mi/h. The radius of the track is 0.320 miles. What is the centr
GREYUIT [131]
The centripetal acceleration of the car is 48,800 mi/h2
4 0
4 years ago
A large ball of Play-Doh with a mass of 0.04kg is launched from a catapult with an initial
ryzh [129]

Answer:

  ≈ 6.68 m/s

Explanation:

A suitable formula is ...

  vf^2 -vi^2 = 2ad

where vi and vf are the initial and final velocities, a is the acceleration, and d is the distance covered.

We note that if the initial launch direction is upward, the velocity of the ball when it comes back to its initial position is the same speed, but in the downward direction. Hence the problem is no different than if the ball were initially launched downward.

Then ...

  vf = √(2ad +vi^2) = √(2·9.8 m/s^2·1.0 m+(5 m/s)^2) = √44.6 m/s

  vf ≈ 6.68 m/s

The ball hits the ground with a speed of about 6.68 meters per second.

__

We assume the launch direction is either up or down.

3 0
3 years ago
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